循环问题

Question

data = new int[6, 6]{{1,0,0,0,0,0},
                      {2,3,5,0,0,0},
                      {4,8,0,0,0,0},
                      {6,0,0,0,0,0},
                      {0,0,0,0,0,0},
                       {0,0,0,0,0,0}}
文本框也定义成数组txs=new Textbox{tx1,tx2,tx3,tx4,tx5,tx6};
怎么样循环将里面的非零输取出来放到6个文本呢？
以下的过程怎么改？
for (int i = 0; i < 6; i++)
            {
                    for (int j = 0; j < 6; j++)
                    {
                        if (data[i, j] != 0)
                        {
                            txs[i].Text = data[i, j].ToString();
                     ]         
                } 

Answer 1

for (int i = 0; i < 6; i++) 
            { 
                    for (int j = 0; j < 6; j++) 
                    { 
                        if (data[i, j] != 0) 
                        { 
                            txs[i].Text = data[i, j].ToString(); 
                    ]        
                } 
这样就可以实现你要结果呀。

Answer 2

楼主要的效果是不是这样，
txt1.Text=1
txt2.Text=235
txt3.Text=4
txt4.Text=6
for (int i = 0; i < 6; i++) 
            { 
                    for (int j = 0; j < 6; j++) 
                    { 
                        if (data[i, j] != 0) 
                        { 
                            txs[i].Text += data[i, j].ToString(); 
                    }     
                

Answer 3

不是啊，我 想要tx1.text=1,tx2.text=2,tx3.text=3,tx4.text=5,tx5.text=4,tx6.text=8,然后因为只有6个文本框所以不能显示后面的6了。

Answer 4

int iTxsSeq = 0;
for (int i = 0; i < 6; i++) 
{ 
   for (int j = 0; j < 6; j++) 
   { 
        if (data[i, j] != 0) 
        { 
            txs[iTxsSeq++].Text = data[i, j].ToString(); 
        }        
   } 
}你的逻辑不对啊，能怪谁。好好读自己写的代码，这么简单的逻辑错误。 我这个代码你还要判断别超过你的txs数组的维数，呵呵
新手太可爱了

Answer 5

int idx=0;
for (int i = 0; i < 6; i++)
            {
                    for (int j = 0; j < 6; j++)
                    {
                        if (data[i, j] != 0)
                        {
                            txs[idx++].Text = data[i, j].ToString();
                        }
                        if (idx>=txs.Length)break;
                    }
                   if (idx>=txs.Length)break;
            } 

Answer 6

data = new string[6,6] { {"stage1,1,step1,95.0,60","stage1,0,step2,0,0","stage1,0,step3,0,0","stage1,0,step4,0,0","stage1,0,step5,0,0","stage1,0,step6,0,0"},
                                 {"stage2,35,step1,95.0,15","stage2,35,step2,55.0,15","stage2,35,step3,72.0,30","stage2,0,step4,0,0","stage2,0,step5,0,0","stage2,0,step6,0,0"},
                                 {"stage3,1,step1,72.0,420","stage3,1,step2,4.0,1","stage3,1,step3,0,0","stage3,1,step4,0,0","stage3,0,step5,0,0","stage3,0,step6,0,0"},
                                 {"stage4,0,step1,0,0","stage4,0,step2,0,0","stage4,0,step3,0,0","stage4,0,step4,0,0","stge4,0,step5,0,0","stage4,0,step6,0,0"},
                                 {"stage5,0,step1,0,0","stage5,0,step2,0,0","stage5,0,step3,0,0","stage5,0,step4,0,0","stage5,0,step5,0,0","stage5,0,step6,0,0"},
                                 {"stage6,0,step1,0,0","stage6,0,step2,0,0","stage6,0,step3,0,0","stage6,0,step4,0,0","stage6,0,step5,0,0","stage6,0,step6,0,0"}
                                };  int m=0;
            int n = 0;
            for (int i = 0; i < 6; i++)
            {
                for (int j = 0; j < 6; j++)
                {
                    s = data[i, j];
                    p = s.Split(new char[] { ',' });
                    if (UInt16.Parse(p[1]) != 0 && p[4] != "0")
                    {
                        stagelbs[m++].Text = p[0];
                        cycletxs[m++].Text = p[1];                        bts[n++].Text = p[2];
                        temps[n++].Text = p[3];
                        times[n++].Text = p[4];
                    }
                    if (m > stagelbs.Length) break;
                    if (n > bts.Length) break;
stagelbs和cycletxs只有3个,bts,temps,times,有6个，
想要显示其中P[1]和P[4]不等于0的字符串。。请教下各位，代码有点长，希望大家耐心看看哈

Answer 7

int[,] data = new int[6, 6] { { 1, 0, 0, 0, 0, 0 }, { 2, 3, 5, 0, 0, 0 }, { 4, 8, 0, 0, 0, 0 }, { 6, 0, 0, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0 }, { 0, 0, 0, 0, 0, 0 } };
            string []s =new string[6];
            int q = 0;
            for (int i = 0; i < 6; i++)
            {
                for (int j = 0; j < 6; j++)
                {
                    if (data[i, j] != 0)
                    {
                        if (q < 6)
                        {
                            s[q] = data[i, j].ToString();
                            q++;
                        }
                    }
                }
            }       

Answer 8

int count=0;
for(int i=0;i<6;i++)
{
for(int j=0;j<6;j++)
{
if(date[i,j]!=0)
{
txt[count++].Text=date[i,j].ToString();
}
}
}

Answer 9

            int data = new int[6, 6]{{1,0,0,0,0,0}, 
                      {2,3,5,0,0,0}, 
                      {4,8,0,0,0,0}, 
                      {6,0,0,0,0,0}, 
                      {0,0,0,0,0,0}, 
                      {0,0,0,0,0,0}};            int[] buff = new int[50];
            int x = 0;
            for (int i = 0; i < 6; i++)
            {
                for (int j = 0; j < 6; j++)
                {
                    if (data[i, j] != 0)
                    {
                        buff[x] = data[i, j];
                        x++;
                    }
                }
            }
            x = 1;
            foreach (TextBox tx in Control)
            {
                if (tx.Name = "textBox" + x.ToString())
                {
                    if (buff[x - 1] != 0)
                    {
                        tx.Text = buff[x - 1].ToString();
                    }
                }
                if ((buff[x - 1] == 0) || ((x - 1) = buff.Length))
                    break;
            }这样似乎是你想要的

Answer 10

能不能让txs[i]的索引是i变量？我想跟我我的数值对应上