遍历xml文件

Question

请问怎样可以遍历xml文件读取每个节点的属性值：
例如如下的xml文件，读取出每个节点的属性first-name的值<?xml version="1.0" encoding="gb2312"?>
<players>
   <player>
 <name first-name="Luis" last-name="Boa Morte"/>
 <player-position english="Midfielder" spanish=""/>
   </player>
   <player>
 <name first-name="Matthew" last-name="Upson"/>
 <player-position english="Defender" spanish=""/>
   </player>
</players>

Answer 1

XmlDocument doc = new XmlDocument();
IList NodeValues = new ArrayList();
doc.Load( Server.MapPath("1.xml") );
XmlNode root = doc.DocumentElement;
foreach (XmlNode personElement in root.SelectSingleNode("FAX").ChildNodes)
{
    NodeValues.Add(personElement.Attributes["first-name"].Value);
}
return IList;

Answer 2

楼主参考XmlReader reader = XmlReader.Create(Server.MapPath("XF.xml"));            while (reader.Read())
            {
                Response.Write("<li>节点类型：" + reader.NodeType + "==<br>");
                switch (reader.NodeType)
                {
                    case XmlNodeType.XmlDeclaration:
                        for (int i = 0; i < reader.AttributeCount; i++)
                        {
                            reader.MoveToAttribute(i);
                            Response.Write("属性：" + reader.Name + "=" + reader.Value + "&nbsp;");
                        }
                        break;
                    case XmlNodeType.Attribute:
                        for (int i = 0; i < reader.AttributeCount; i++)
                        {
                            reader.MoveToAttribute(i);
                            Response.Write("属性：" + reader.Name + "=" + reader.Value + "&nbsp;");
                        }
                        break;
                    case XmlNodeType.CDATA:
                        Response.Write("CDATA:" + reader.Value + "&nbsp;");
                        break;
                    case XmlNodeType.Element:
                        Response.Write("节点名称：" + reader.LocalName + "<br>");
                        for (int i = 0; i < reader.AttributeCount; i++)
                        {
                            reader.MoveToAttribute(i);
                            Response.Write("属性：" + reader.Name + "=" + reader.Value + "&nbsp;");
                        }
                        break;
                    case XmlNodeType.Comment:
                        Response.Write("Comment:" + reader.Value);
                        break;
                    case XmlNodeType.Whitespace:
                        Response.Write("Whitespace:" + "&nbsp;");
                        break;
                    case XmlNodeType.ProcessingInstruction:
                        Response.Write("ProcessingInstruction:" + reader.Value);
                        break;
                    case XmlNodeType.Text:
                        Response.Write("Text:" + reader.Value);
                        break;
                }
            }
            reader.Close();

Answer 3

如果你的结构不做大的变化的话，不需要遍历，直接使用SelectNodes就可以了。            XmlDocument doc = new XmlDocument();
            doc.Load("..\\..\\XMLFile1.xml");            foreach (XmlNode node in doc.SelectNodes("/players/player/name"))
            {
                Console.WriteLine(node.Attributes["first-name"].Value.ToString());
            }XMLFile1.xml的内容就是你的xml。

Answer 4

 XmlReader reader = XmlReader.Create(Server.MapPath("XF.xml"));            while (reader.Read())
            {                switch (reader.NodeType)
                {                    case XmlNodeType.Element:                        for (int i = 0; i < reader.AttributeCount; i++)
                        {
                            reader.MoveToAttribute(i);
                            if (reader.Name == "first-name")
                            {
                                Response.Write(reader.Name + "=" + reader.Value + "&nbsp;");
                            }
                        }
                        break;                }
            }
            reader.Close();

Answer 5

XmlDocument doc = new XmlDocument();
IList NodeValues = new ArrayList();
doc.Load( Server.MapPath("1.xml") );
XmlNode root = doc.DocumentElement;
foreach (XmlNode personElement in root.SelectSingleNode("("/players/player").ChildNodes)
{
    NodeValues.Add(personElement.Attributes["first-name"].Value);
}
return IList;

Answer 6

用个DataSet先Read进来再来一循环，简单多了

Answer 7

看看这个吧           
fileName = "images/" + fileName;
            XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.Load(Server.MapPath("~/FocusList.xml"));
            XmlNode root = xmlDoc.SelectSingleNode("Image"); //查找<bookstore> 
            XmlNodeList xnl = xmlDoc.SelectSingleNode("Image").ChildNodes;
            if (xnl != null && xnl.Count > 0)
            {
                foreach (XmlNode xn in xnl)
                {
                    
                    for (int i = 0; i < xnl.Count - 4;i++ )
                    {
                        //删除最靠前的一个节点
                        xn.ParentNode.RemoveChild(xn);
                    }
                }
            }
           
            string str = DateTime.Now.ToString("yyyy:MM:dd hh:mm:ss fff");
            XmlElement xe1 = xmlDoc.CreateElement("Focus");//创建一个<Focus>节点 
            xe1.SetAttribute("ID", "" + modelID + "");//设置该节点ID属性 
            XmlElement xesub1 = xmlDoc.CreateElement("Title");
            xesub1.InnerText = TrueName;//设置文本节点 
            xe1.AppendChild(xesub1);//添加到<Focus>节点中 
            XmlElement xesub2 = xmlDoc.CreateElement("Path");
            xesub2.InnerText = fileName;
            xe1.AppendChild(xesub2);
            root.AppendChild(xe1);//添加到<image>节点中 
            xmlDoc.Save(Server.MapPath("~/FocusList.xml"));
            return true;

Answer 8

public ArrayList GetAttribute()
    {
        XmlDocument xmlDoc = new XmlDocument();
        xmlDoc.Load(Server.MapPath("XMLFile.xml"));
        ArrayList al = new ArrayList();
        XmlNodeList xmlNL = xmlDoc.SelectNodes("players/player");
        foreach (XmlNode xmlN in xmlNL)
        {
            XmlElement xe = (XmlElement)xmlN.SelectSingleNode("name");
            al.Add(xe.GetAttribute("first-name"));
        }
        return al;
    }这个看下，测试没问题。返回的ArrayList

Answer 9

        XmlNodeList nodes = xmlDoc.SelectNodes("//@first-name");
        foreach (XmlNode node in nodes)
        {
              //node.Value;
        }