C#cs文件中如何用程序打开客户端程序呀

解决方案 »

  1.   

    System.Diagnostics.Process.Start("notepad.exe");
      

  2.   

    System.Diagnostics.Process xxx;
    xxx= new System.Diagnostics.Process();
    xxx.StartInfo.FileName = "路径";
    xxx.Start();
      

  3.   

                System.Diagnostics.ProcessStartInfo info = new System.Diagnostics.ProcessStartInfo();
                System.Diagnostics.Process proc = new System.Diagnostics.Process();
                info.FileName = "calc.exe";
                info.Arguments = "";
                info.WorkingDirectory = @"c:\windows\";
                proc = System.Diagnostics.Process.Start(info);