double[,] jk = new double[5, 2];
                     .
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                     .
                     .
            foreach (int x in jk)
                sum1 += x;
            foreach (int x in jk)
                sum2 += x;目的是将[,0]的列求和,然后[,1]的列求和

解决方案 »

  1.   

    for(int i=0;i<5;i++)
    {
     sum1+=j[i,0];
     sum2+=j[i,1];
    }
      

  2.   

    个人认为这种情况并不适合用foreach
      

  3.   

      double[,] jk = new double[5, 2];
                          double _Sum1 = 0;
                double _Sum2 = 0;
                int _Index =1;
                foreach (double x in jk)
                {
                    if (_Index % 2 == 0)
                    {
                        _Sum2 += x;                   
                    }
                    else
                    {
                        _Sum1 += x;
                    }
                    _Index++;
                }