像这样的两个函数，仅仅是一个函数参数的不同，就要写成两个函数，请高手赐教了，如何写成一个函数来代替。请看代码：

Question

像这样的两个函数，仅仅是一个函数参数的不同，就要写成两个函数，请高手赐教了，如何写成一个函数来代替。请看代码：
            private int FindListElementIndex1(stationPoint SP)
            {
                int n;
                n = -1;
                foreach (var p in PointNxEyCollect)
                {
                    n++;
                    if (p.pointNumber == SP.pointNumber)
                    {
                        break;
                    }
                }
                return n;
            }...........................................................................            private int FindListElementIndex(aimAtPoint ap)
            {
                int k = -1;
                foreach (var p in PointNxEyCollect)
                {
                    k++;
                    if (p.pointNumber == ap.pointNumber)
                    {
                        break;
                    }
                }
                return k;
            }
变量说明：
            List<Point> PointNxEyCollect = new List<Point>();
            List<stationPoint> stationPointCollect = new List<stationPoint>();
            List<aimAtPoint> aimAtPointCollect = new List<aimAtPoint>();

Answer 1

用List<T>作为参数，实现重载

Answer 2

抽象出接口...这两个方法都只用到了aimAtPoint和stationPoint的一个属性pointNumber，Point也有这个属性...用接口可以解除三者的耦合...

Answer 3

看这个：
http://www.cnblogs.com/anlyren/archive/2008/01/25/simple_Factory_Pattern.html

Answer 4

          成员pointNumber的数据类型是什么？假如是int吧: 
            private int FindListElementIndex(int poingNumber) 
            { 
                int k = -1; 
                foreach (var p in PointNxEyCollect) 
                { 
                    k++; 
                    if (p.pointNumber == poingNumber) 
                    { 
                        break; 
                    } 
                } 
                return k; 
            } 

Answer 5

仅仅是个例子...还可以优化得更好，按你的需求去设计...interface IPoint
{
int pointNumber{get;set;}
}            List <IPoint> PointNxEyCollect = new List <IPoint>(); 
            private int FindListElementIndex(IPoint ap) 
            {
                int k = -1; 
                foreach (var p in PointNxEyCollect) 
                { 
                    k++; 
                    if (p.pointNumber == ap.pointNumber) 
                    { 
                        break; 
                    } 
                } 
                return k; 
            }