求一个数组算法，不，是解法，只要能解就谢谢了。（80分，在线等~）

Question

求一个算法，我有一个数组{1,1,4,3,3},或{2,3,5,5,1}{1,1,4,3,3}:找出相同的数,并相加存下来{2,4,6}{2,3,5,5,1}:{2,3,10,1}

Answer 1

 int[] _Temp = new int[] { 1, 1, 4, 3, 3 };            
            IList<int> _Value = new List<int>();
            IList<int> _ValueCount = new List<int>();
                        for (int i = 0; i != _Temp.Length; i++)
            {
                int _Index = _Value.IndexOf(_Temp[i]);
                if (_Index == -1)
                {
                    _Value.Add(_Temp[i]);
                    _ValueCount.Add(1);
                }
                else
                {
                    _ValueCount[_Index]++;
                }
            }            int[] _IntValue = new int[_Value.Count];            for (int i = 0; i != _Value.Count; i++)
            {
                _IntValue[i] = _Value[i] * _ValueCount[i];
            }            

Answer 2

你把所有的int换成 double不就好了~~

Answer 3

谢谢，如果是{s,s,d,c,c}
那又如何{ss,d,cc}

Answer 4

 int[] ints = new int[] { 2, 3, 5, 5, 1 };
        int length = ints.Length;
        int[] ints2 = new int[length];
        int length2 = 0;
        for (int i = 0; i < length; i++)
        {
            int thisint = ints[i];
            bool isget = true;
            for (int j = 0; j < length2; j++)
            {
                if (ints[j] == thisint)
                {
                    isget = false;
                    break;
                }
            }
            if (isget)
            {
                int thisintsum = thisint;
                for (int j = i + 1; j < length; j++)
                {
                    if (ints[j] == thisint)
                    {
                        thisintsum += thisint;
                    }
                }
                ints2[length2] = thisintsum;
                length2++;
            }
        }
        int[] ints3 = new int[length2];
        Array.Copy(ints2, 0, ints3, 0, length2);

Answer 5

string[] ints = new string[] { "2", "3", "5", "5", "1" };
        int length = ints.Length;
        string[] ints2 = new string[length];
        int length2 = 0;
        for (int i = 0; i < length; i++)
        {
            string thisint = ints[i];
            bool isget = true;
            for (int j = 0; j < length2; j++)
            {
                if (ints[j] == thisint)
                {
                    isget = false;
                    break;
                }
            }
            if (isget)
            {
                string thisintsum = thisint;
                for (int j = i + 1; j < length; j++)
                {
                    if (ints[j] == thisint)
                    {
                        thisintsum += thisint;
                    }
                }
                ints2[length2] = thisintsum;
                length2++;
            }
        }
        string[] ints3 = new string[length2];
        Array.Copy(ints2, 0, ints3, 0, length2);
//改下变量类型就好

Answer 6

net3.0以上版本直接使用linq就可以了 
var Girls = new[] {"Christine", "Eva", "Jean", "Novia", "Winnie"};
var PMs = new[] {"Eva", "Novia", "Vincent", "Williams", "Winnie"};  
 // 是 Girl 且是 PM (交集) 
foreach (var s in Girls.Intersect(PMs))  
{   
Console.WriteLine(s
}  
Console.WriteLine();如果是net2.0的话，请参考 
http://blog.blueshop.com.tw/uni2tw/archive/2008/02/14/54315.aspx 

Answer 7

有点乱不过功能实现了。int[] a = { 1, 3, 4,4,1, 1, 3, 3 };                       List<int> aa = new List<int>();
            List<int> bb = new List<int>();
            List<int> ll = new List<int>();
            for (int i = 0; i < a.Length; i++)
            {
                aa.Add(a[i]);
            }         
            int cou = 0;
           
            for (int i = 0; i < aa.Count; i++)
            {
                while ((len = aa.IndexOf(aa[i], ++len)) >= 0)
                {
                    cou++;
                    ll.Add(aa[len]);
                }
                if (cou != 0)
                {
                    bb.Add(cou * aa[i]);
                }
                else
                {
                    bb.Add(aa[i]);
                }
                cou = 0;                for (int j = 0; j < ll.Count; j++)
                {
                    aa.Remove(ll[j]);
                }                               
            }

Answer 8

少写了个变量：int len ＝ 0；cou后面

Answer 9

晕了，int len ＝ －1；

Answer 10

妈的，我认为这个有点简单却用了一上午的时间，唉~~~~~~~~~~
List<string> int_33 = new List<string> ( );//重复的数
            List<string> int_11 = new List<string> ( );//不重复的数            List<string> ints = new List<string> { "2" , "2" , "1" , "5" , "5" , "2" , "2","3" };
            List<string> ints_1 = new List<string> { "2" , "5" };
            foreach ( string s in ints_1 )
            {
                foreach ( string str in ints )
                {
                    if ( s == str )
                        int_11.Add ( str );                
                }
                string sTmp = "";
                if ( int_11.Count > 0 )
                {
                    foreach ( string stri in int_11 )
                    {
                        sTmp += stri;
                    }
                    int_33.Add ( sTmp );
                    int_11.Clear ( );
                }
            }
            bool b = false;
            foreach ( string s in ints )
            {
                foreach ( string str in ints_1 )
                {
                    if ( s == str )
                    {
                        b = true;
                        continue;
                    }
                }
                if ( b == false )
                {
                    int_11.Add ( s );
                }
                b = false;
            }
还是要谢谢各位，把分数分了

Answer 11

List<string> int_33 = new List<string> ( );//重复的数
            List<string> int_11 = new List<string> ( );//不重复的数            List<string> ints = new List<string> { "2" , "2" , "1" , "5" , "5" , "2" , "2","3" };
            List<string> ints_1 = new List<string> { "2" , "5" };
            foreach ( string s in ints_1 )
            {
                foreach ( string str in ints )
                {
                    if ( s == str )
                        int_11.Add ( str );                
                }
                string sTmp = "";
                if ( int_11.Count > 0 )
                {
                    foreach ( string stri in int_11 )
                    {
                        sTmp += stri;
                    }
                    int_33.Add ( sTmp );
                    int_11.Clear ( );
                }
            }
            bool b = false;
            foreach ( string s in ints )
            {
                foreach ( string str in ints_1 )
                {
                    if ( s == str )
                    {
                        b = true;
                        continue;
                    }
                }
                if ( b == false )
                {
                    int_11.Add ( s );
                }
                b = false;
            }