读取xml

Question

<Employees>
  <NO1>
    <UserName></UserName>
    <UserPhone></UserPhone>
    <MailAddress></MailAddress>
    <Email></Email>
    <DeviceID>yy</DeviceID>
    <Vendors></Vendors>
    <VendorsrPhone>
</VendorsrPhone>
    <Experience>as</Experience>
    <BuyDate>2008-08-07 </BuyDate>
  </NO1>
</Employees>我想要的读取到的值为str=";;;;yy;;;as;2008-08-07"就是读取NO1节点下所有节点的text(即使为空)

Answer 1

XmlTextReader reader=new XmlTextReader("你的文件名"); string key = ""; try
     {
        while(reader.Read())
        {
         if (reader.NodeType==XmlNodeType.Element)
            {
             if (reader.Name=="UserName")
                        {
                            key = reader.ReadElementString().Trim();
                            info.Add(key, "");
                        }   
            ....
             }
         }
     }
catch(System.Exception e)   
  {
     MessageBox.Show(e.ToString());
  }
 finally
 {
 if (reader!=null)
 {
    reader.Close();
  }
}
大致就是这个框架吧

Answer 2

  XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.Load(@"D:\Project\C#Test\WindowsApplication1\WindowsApplication4\XMLFile1.xml");
            
            XmlNode node = xmlDoc.SelectSingleNode("/Employees/NO1");
string str="";
Foreach(XmlNode n in node.ChildNodes)
{
str=str+n.InnerText+";";
}

Answer 3

XmlDocument doc= new XmlDpcument();
doc.load(XML路径);
XmlNodeList nodes =doc.GetNodesByTag("NO1");
foreach(XmlNode n in nodes)
{
string str ="";
str +=node.ChildNodes.Item(0).InnerText;
str +=node.ChildNodes.Item(1).InnerText;
str +=node.ChildNodes.Item(2).InnerText;
str +=node.ChildNodes.Item(3).InnerText;
str +=node.ChildNodes.Item(4).InnerText;
str +=node.ChildNodes.Item(5).InnerText;
str +=node.ChildNodes.Item(6).InnerText;
str +=node.ChildNodes.Item(7).InnerText;
str +=node.ChildNodes.Item(8).InnerText;}

Answer 4

        private void button1_Click(object sender, EventArgs e)
        {
            StringBuilder sb = new StringBuilder();
            StringReader sr = new StringReader(richTextBox1.Text);
            XPathDocument doc = new XPathDocument(sr);
            XPathNavigator nav = doc.CreateNavigator();
            XPathNodeIterator iter = nav.Select("/Employees/NO1");
            while (iter.MoveNext())
            {
                XPathNodeIterator xpthIter = iter.Current.SelectChildren(XPathNodeType.Element);
                while (xpthIter.MoveNext())
                {
                    richTextBox2.AppendText(";"+xpthIter.Current.ToString());
                }
                
            }
        }

Answer 5

测试通过
        private void button1_Click(object sender, EventArgs e)
        {
            StringBuilder sb = new StringBuilder();
            StringReader sr = new StringReader(richTextBox1.Text);
            XPathDocument doc = new XPathDocument(sr);
            XPathNavigator nav = doc.CreateNavigator();
            XPathNodeIterator iter = nav.Select("/Employees/NO1");
            while (iter.MoveNext())
            {
                XPathNodeIterator xpthIter = iter.Current.SelectChildren(XPathNodeType.Element);
                while (xpthIter.MoveNext())
                {
                    richTextBox2.AppendText(";"+xpthIter.Current.ToString());
                }
                
            }
        }

Answer 6

;;;;;yy ;;;as ;2008-08-07这就是结果

Answer 7

XmlDocument xmlDoc = new XmlDocument();
   xmlDoc.Load(@"D:\Project\C#Test\WindowsApplication1\WindowsApplication4\XMLFile1.xml");
     
  XmlNode node = xmlDoc.SelectSingleNode("/Employees/NO1");
string str="";
Foreach(XmlNode n in node.ChildNodes)
{
str=str+n.InnerText+";";
｝
二楼正解！！！建议楼主结贴了