我有一个Xml，如何填充到treeview！xml层次不限。

Question

xml层次不限。
自己写了一个递归。速度太慢了！
求广法。给些代码参考也可。

Answer 1

考虑使用XSLT直接将你的XML转换成目标HTML

Answer 2

我的想法,读取xml应该比较慢,你可以这样,用 dataset的 ReadXml()方法,把xml数据读成datatable,然后操作,我感觉这样应该比较快

Answer 3

http://www.cnblogs.com/wuchang/archive/2006/12/01/578719.html

Answer 4

同4楼
lz可否提供些xml片断

Answer 5

<Z><Dic name="zepto-" Algebra="0" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zepto-.xml" Grade="k7,k8,k9-12"/><Dic name="zero" Algebra="1" Geometry="0" Measurement="0" NumberSense="1" Statistics="0" filePath="z/zero.xml" Grade="k2,k3,k4,k5,k6,k7,k8,k9-12"/><Dic name="zero matrix (null matrix)" Algebra="1" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zeromatrixnullmatrix.xml" Grade="k7,k8,k9-12"/><Dic name="zero property of addition" Algebra="1" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zeropropertyofaddition.xml" Grade="k2,k3,k4,k5,k6,k7,k8,k9-12"/><Dic name="zero property of multiplication" Algebra="1" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zeropropertyofmultiplication.xml" Grade="k3,k4,k5,k6,k7,k8,k9-12"/><Dic name="zetta-" Algebra="0" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zetta-.xml" Grade="k7,k8,k9-12"/><Dic name="zone" Algebra="0" Geometry="0" Measurement="0" NumberSense="0" Statistics="0" filePath="z/zone.xml" Grade="k7,k8,k9-12"/></Z>

Answer 6

        private void button1_Click(object sender, EventArgs e)
        {
            try
            {
                XmlDocument xmlDoc = new XmlDocument();
                xmlDoc.Load(textBox1.Text);                XmlNodeList xmlNodes = xmlDoc.DocumentElement.ChildNodes;                this.treeView1.BeginUpdate();
                this.treeView1.Nodes.Clear();
                treeView1.Nodes.Add(new TreeNode(xmlDoc.DocumentElement.Name));
                ReadTreeNode(xmlNodes, this.treeView1.Nodes[0].Nodes);
                this.treeView1.EndUpdate();
            }
            catch (Exception e)
            {
                                                
            }
        }
        private void ReadTreeNode(XmlNodeList xmlNode, TreeNodeCollection treeNode)
        {
            foreach (XmlNode var in xmlNode)
            {
                if (var.NodeType != XmlNodeType.Element)
                {
                    continue;
                }
                
                TreeNode newTreeNode = new TreeNode();                                if (var.HasChildNodes)
                {
                    newTreeNode.Text = var.Name;
                    ReadTreeNode(var.ChildNodes, newTreeNode.Nodes);
                }
                else
                {
                    if (var.Attributes.Count !=0)
                        newTreeNode.Text = var.Attributes[0].Value;
                    else
                        newTreeNode.Text = var.Name;
                }                
                treeNode.Add(newTreeNode);
            }
        }