完整的C#公历转农历的源代码 急用 在线等 先表示感谢 非常谢谢能帮忙,我现在只有2011年以前的,希望哪位能给个能到2050年以后的 [email protected] 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 #region 农历日期 //农历日期 private static string[] DayName = {"*","初一","初二","初三","初四","初五", "初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"}; //农历月份 private static string[] MonthName = { "*", "正", "二", "三", "四", "五", "六", "七", "八", "九", "十", "十一", "腊" }; //公历月计数天 private static int[] MonthAdd = { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 }; //农历数据 private static int[] LunarData = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438 ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402 ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738 ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762 ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413 ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395 ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031 ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222 ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709 ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877}; /// <summary> /// 获取对应日期的农历 /// </summary> /// <param name="dtDay">公历日期</param> /// <returns></returns> public string GetLunarCalendar(DateTime dtDay) { string sYear = dtDay.Year.ToString(); string sMonth = dtDay.Month.ToString(); string sDay = dtDay.Day.ToString(); int year; int month; int day; try { year = int.Parse(sYear); month = int.Parse(sMonth); day = int.Parse(sDay); } catch { year = DateTime.Now.Year; month = DateTime.Now.Month; day = DateTime.Now.Day; } int nTheDate; int nIsEnd; int k, m, n, nBit, i; string calendar = string.Empty; //计算到初始时间1921年2月8日的天数:1921-2-8(正月初一) nTheDate = (year - 1921) * 365 + (year - 1921) / 4 + day + MonthAdd[month - 1] - 38; if ((year % 4 == 0) && (month > 2)) nTheDate += 1; //计算天干,地支,月,日 nIsEnd = 0; m = 0; k = 0; n = 0; while (nIsEnd != 1) { if (LunarData[m] < 4095) k = 11; else k = 12; n = k; while (n >= 0) { //获取LunarData[m]的第n个二进制位的值 nBit = LunarData[m]; for (i = 1; i < n + 1; i++) nBit = nBit / 2; nBit = nBit % 2; if (nTheDate <= (29 + nBit)) { nIsEnd = 1; break; } nTheDate = nTheDate - 29 - nBit; n = n - 1; } if (nIsEnd == 1) break; m = m + 1; } year = 1921 + m; month = k - n + 1; day = nTheDate; string date = year + "-" + month + "-" + day; return MonthName[month] + "月" + DayName[day]; } #endregion调用GetLunarCalendar(DateTime dtDay)方法就可以了,返回一个农历日期字符串。 c#2.0之后可以用System.Globalization.ChineseLunaCalendar(忘了是不是这么写的,反正肯定有类似的) System.Globalization.ChineseLunisolarCalendar supports up to year 2101Also you might look into jianghanxia's contribution, which seems very handy:http://www.cnblogs.com/Files/jianghanxia/ChineseLunisolar.rar System.globalization.chineselunisolarcalendar 1.0 的到2050年比较麻烦2.0 可以看看这个http://www.xrss.cn/Info/10617.Html datagridviewcomboboxcolumn 有时选择下拉时,背景色为什么变了颜色 关于C#的学习一点想法 跪求解决办法!!! 怎么按顺序弹出两个提示框 一个小问题请大家帮忙,关于bitmap方面的 问一个很痴的问题~~~ WPF中image控件显示图像问题 如何将缓冲区的指针传给Com? 哪里有《C#入门经典》电子版的下载!!! 求C#读写dwg文件(不使用AntoCAD环境)的开源插件或代码! 求lucene .net下的学习资料 32位色的异形的边缘光滑的窗口怎么做?
#region 农历日期
//农历日期
private static string[] DayName = {"*","初一","初二","初三","初四","初五",
"初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五",
"十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五",
"廿六","廿七","廿八","廿九","三十"}; //农历月份
private static string[] MonthName = { "*", "正", "二", "三", "四", "五", "六", "七", "八", "九", "十", "十一", "腊" }; //公历月计数天
private static int[] MonthAdd = { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334 };
//农历数据
private static int[] LunarData = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438
,3402,3749,331177,1453,694,201326,2350,465197,3221,3402
,400202,2901,1386,267611,605,2349,137515,2709,464533,1738
,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762
,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413
,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395
,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031
,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222
,268949,3402,3493,133973,1386,464219,605,2349,334123,2709
,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
/// <summary>
/// 获取对应日期的农历
/// </summary>
/// <param name="dtDay">公历日期</param>
/// <returns></returns>
public string GetLunarCalendar(DateTime dtDay)
{
string sYear = dtDay.Year.ToString();
string sMonth = dtDay.Month.ToString();
string sDay = dtDay.Day.ToString();
int year;
int month;
int day;
try
{
year = int.Parse(sYear);
month = int.Parse(sMonth);
day = int.Parse(sDay);
}
catch
{
year = DateTime.Now.Year;
month = DateTime.Now.Month;
day = DateTime.Now.Day;
} int nTheDate;
int nIsEnd;
int k, m, n, nBit, i;
string calendar = string.Empty;
//计算到初始时间1921年2月8日的天数:1921-2-8(正月初一)
nTheDate = (year - 1921) * 365 + (year - 1921) / 4 + day + MonthAdd[month - 1] - 38;
if ((year % 4 == 0) && (month > 2))
nTheDate += 1;
//计算天干,地支,月,日
nIsEnd = 0;
m = 0;
k = 0;
n = 0;
while (nIsEnd != 1)
{
if (LunarData[m] < 4095)
k = 11;
else
k = 12;
n = k;
while (n >= 0)
{
//获取LunarData[m]的第n个二进制位的值
nBit = LunarData[m];
for (i = 1; i < n + 1; i++)
nBit = nBit / 2;
nBit = nBit % 2;
if (nTheDate <= (29 + nBit))
{
nIsEnd = 1;
break;
}
nTheDate = nTheDate - 29 - nBit;
n = n - 1;
}
if (nIsEnd == 1)
break;
m = m + 1;
}
year = 1921 + m;
month = k - n + 1;
day = nTheDate;
string date = year + "-" + month + "-" + day;
return MonthName[month] + "月" + DayName[day];
}
#endregion调用GetLunarCalendar(DateTime dtDay)方法就可以了,返回一个农历日期字符串。
System.globalization.chineselunisolarcalendar
http://www.xrss.cn/Info/10617.Html