关于XML的读写问题!!

Question

<?xml version="1.0" encoding="utf-8" ?> 
<book>
<lovel>
<name>jim</name>
<author>罗曼罗兰</author>
</lovel>
<lovel>
<name>lucy</name>
<author>杰克逊</author>
</lovel>
</book>我可以根据"jim"找到"罗曼罗兰"这个信息吗?
要是有的话，怎么的一个读法，还有就是怎么添加节点！！！我刚刚接触XML，急着用，没办法，请各位帮忙！！！！！

Answer 1

<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<MotherTongue lalTitle = "24小时天气预报"
  lalWeatherType = "天气类型"
  lalMax = "最高温度"
  lalMin = "最低温度"
  btnSet="设置"
  title="天气预报" 
  btnCancel="取消"
     >
</MotherTongue>
<English lalTitle = "24-hour weather forecast"
  lalWeatherType = "weather type"
  lalMax = "maximum temperature"
  lalMin = "minimum temperature"
  btnSet="set"
  title="weather forecast" 
  btnCancel="cancel"
             >
</English>
</configuration>
  void LoadCfgFile()
        {            XmlDocument x = new XmlDocument();
            x.Load("LanguageXml/WeatherForm.xml");
            switch (MainForm._nLanguage)
            {
                case 1:
                    XmlNodeList xnl = x.SelectNodes("/configuration/MotherTongue");
                    this.lalMax.Text = xnl[0].Attributes["lalMax"].InnerText;
                    this.lalMin.Text = xnl[0].Attributes["lalMin"].InnerText;
                    this.lalTitle.Text = xnl[0].Attributes["lalTitle"].InnerText;
                    this.btnSet.Text = xnl[0].Attributes["btnSet"].InnerText;
                    this.btnCancel.Text = xnl[0].Attributes["btnCancel"].InnerText;
                    this.lalWeatherType.Text = xnl[0].Attributes["lalWeatherType"].InnerText;
                    this.Text = xnl[0].Attributes["title"].InnerText;
                    break;
                case 2:
                    XmlNodeList xnl1 = x.SelectNodes("/configuration/English");
                    this.lalMax.Text = xnl1[0].Attributes["lalMax"].InnerText;
                    this.lalMin.Text = xnl1[0].Attributes["lalMin"].InnerText;
                    this.lalTitle.Text = xnl1[0].Attributes["lalTitle"].InnerText;
                    this.btnSet.Text = xnl1[0].Attributes["btnSet"].InnerText;
                    this.btnCancel.Text = xnl1[0].Attributes["btnCancel"].InnerText;
                    this.lalWeatherType.Text = xnl1[0].Attributes["lalWeatherType"].InnerText;
                    this.Text = xnl1[0].Attributes["title"].InnerText;
                    break;            }
        }

Answer 2

用我这个，包你搞定，接分~~static string Search()
        {
            string author="";
            XmlDocument doc = new XmlDocument();
            doc.Load(@"你XML文件的路径");
            XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
            foreach (XmlNode xn in nodelist)
            {               
                string name = node.SelectSingleNode("name").InnerText;
                if(name.equal("jim"))
                {
                    author= node.SelectSingleNode("author").InnerText;
                }
            }
            return author;
       }

Answer 3

XmlNode node = doc.SelectSingleNode("/book/lovel[name='jim']/author");
node.InnerText就是

Answer 4

二楼的大虾请回答：
说node没有定义，应该是什么类型的？还有就是你的一点错误，String中不含equal()而是Equals()

Answer 5

static string Search()
        {
            
            string author = "";
            XmlDocument doc = new XmlDocument();
            doc.Load("I:\\book.xml");
            XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
            XmlNode node = doc.SelectSingleNode("/book/lovel[name='jim']/author"); 
            foreach (XmlNode xn in nodelist)
            {
                string name = node.SelectSingleNode("name").InnerText;
                if (Object.Equals(name, "jim"))
                {
                    author = node.SelectSingleNode("author").InnerText;
                }
            }
            return author;
        }string name = node.SelectSingleNode("name").InnerText;
这句话老出错！！
说什么"new"关键字创建对象实例；调用前检查确定对象是否为空！！我把它先定义String name = "name";
还是不行！！怎么回事？？？

Answer 6

static string Search()
        {
            string author="";
            XmlDocument doc = new XmlDocument();
            doc.Load("你XML文件的路径");
            XmlNodeList nodelist = doc.SelectSingleNode("book").ChildNodes;
            foreach (XmlNode xn in nodelist)
            {               
                string name = xn.SelectSingleNode("name").InnerText;
                if(name.equal("jim"))
                {
                    author= xn.SelectSingleNode("author").InnerText;
                }
            }
            return author;
       }

Answer 7

12楼正解，不过还是要改一个地方：
name.equal("jim") 改为 name.Equals("jim")谢谢各位的热心帮忙结贴，散分喽！！！！
哈哈哈