在一个表达式中如何读取数字和其他字符

Question

比如：输入字符串2+45+435*34+(3*5)+4   输出2，+，45，+，435即把每个字符都输出来

Answer 1

string str = "2+45+435*34+(3*5)+4";
            char[] num = new char[100];
            char[] other = new char[100];
            int i = 0;
            int j = 0;
            foreach (char ch in str)
            {
                if (Char.IsNumber(ch))
                {
                    num[i++] = ch;
                }
                else
                {
                    other[j++] = ch;
                }
            }

Answer 2

string str = "2+45+435*34+(3*5)+4";
            char[] num = new char[100];
            char[] other = new char[100];
            int i = 0;
            int j = 0;
            foreach (char ch in str)
            {
                if (Char.IsNumber(ch))
                {
                    num[i++] = ch;
                }
                else
                {
                    other[j++] = ch;
                }
            }

Answer 3

        string text = "2+45+435*34+(3*5)+4";
　      public void Disp()
        {
            for (int i = 0; i < text.Length; i++)
            {
                //为了看清效果，这里分行输出
                Console.WriteLine(text.Substring(i, 1));
            }
        }
前面的接收字符串的逻辑我就不写了，那很简单.

Answer 4

        private string GetResult(string express)
        {
            string result=string.Empty;
            string temp="";
            foreach (char c in express)
            {
                if (char.IsDigit(c)) temp += c.ToString();
                else
                {
                    if (temp != "") result += temp + ",";
                    result += c.ToString() + ",";
                    temp = "";
                }
            }
            if (temp != "") result += temp;
            return result.TrimEnd(",");
        }

Answer 5

List<char> chars = new List<char>();
List<string> result = new List<string>();
string str = "2+45+435*34+(3*5)+4"; 
 for(int i = 0;i < str.Length; i ++)
            { 
                if (!Char.IsNumber(str[i])) 
                { 
                    if(chars.Count > 0)
                    {
                        result.Add(new string(chars.ToArray()));
                        chars.Clear();
                    }
                    result.Add(str[i].ToString());
                } 
                else 
                { 
                    chars.Add(str[i]); 
                } 
            }按顺序输出result里面的item即可。

Answer 6

        private string GetResult(string express)
        {
            string result=string.Empty;
            string temp="";
            foreach (char c in express)
            {
                if (char.IsDigit(c)) temp += c.ToString();
                else
                {
                    if (temp != "") result += temp + ",";
                    result += c.ToString() + ",";
                    temp = "";
                }
            }
            if (temp != "") result += temp;
            return result.TrimEnd(',');//上面有误，这里要换成单引。。
        }

Answer 7

2楼 534 也是char类型？？？？

Answer 8

System.Text.RegularExpressions.Regex regexp = new System.Text.RegularExpressions.Regex(@"\d+|\D");
            System.Text.RegularExpressions.MatchCollection matchs =  regexp.Matches("2+45+435*34+(3*5)+4");            foreach (System.Text.RegularExpressions.Match match in matchs)
            {
                System.Console.Write(match.Value+",");
            }