C# 使程序开启是自动运行

Question

C#  开发WINFORM 程序 使开机时自动运行

Answer 1

  
  /// <summary>
    /// 注册表操作
    /// </summary>
    public class WinRegistryKey
    {
        //自动运行，keyname 是你自定义的注册表键，可以自己取个名字，filepath是要自动运行的程序路径
        public static bool SetAutoRun(string keyName, string filePath)
        {
            try
            {
                RegistryKey runKey = Registry.LocalMachine.OpenSubKey(@"\SOFTWARE\Microsoft\Windows\CurrentVersion\Run", true);
                runKey.SetValue(keyName, filePath);
                runKey.Close();
            }
            catch
            {
                return false;
            }
            return true;
        }//取消自动运行
        public static bool UnSetAutoRun(string keyName)
        {
            try
            {
                RegistryKey runKey = Registry.LocalMachine.OpenSubKey(@"\SOFTWARE\Microsoft\Windows\CurrentVersion\Run", true);                if (runKey.GetValue(keyName) != null)
                {
                    runKey.DeleteValue(keyName);
                }
                runKey.Close();
            }
            catch
            {
                return false;
            }
            return true;           
        }    }