帮忙看下 C++转成C#

Question

struct PROG_INFO
{
int nProgID;
int nSize;
int nUpLoadSize;
int nServiceID;
int nFileCount;
int nState;
int nSpeed;
int nCostTime;
LPSTR szName;
PROG_INFO()
{
nProgID = 0;
nSize = 0;
nUpLoadSize = 0;
nServiceID = 0;
nFileCount = 0;
nState = 0;
nSpeed = 0;
nCostTime =0;
szName = NULL;
}
};我转成了：
        public class PROG_INFO
        {
            public int nProgID;
            public int nSize;
            public int nUpLoadSize;
            public int nServiceID;
            public int nFileCount;
            public int nState;
            public int nSpeed;
            public int nCostTime;
            public string szName;
            public PROG_INFO(IntPtr wParam)
            {
                nProgID = 0;
                nSize = 0;
                nUpLoadSize = 0;
                nServiceID = 0;
                nFileCount = 0;
                nState = 0;
                nSpeed = 0;
                nCostTime = 0;
                szName = null;
            }
        }
这样有问题么？请各位帮忙看看谢了
structc#c++

Answer 1

public PROG_INFO(IntPtr wParam）
这个是什么意思，好像不需要这个参数把？

Answer 2

只要LPSTR 换成string就可以了

Answer 3

 public struct PROG_INFO
    {
        public int nProgID;
        public int nSize;
        public int nUpLoadSize;
        public int nServiceID;
        public int nFileCount;
        public int nState;
        public int nSpeed;
        public int nCostTime;        [System.Runtime.InteropServices.MarshalAs(System.Runtime.InteropServices.UnmanagedType.LPStr)]
        public string szName;        public PROG_INFO(IntPtr wParam)
        {
            nProgID = 0;
            nSize = 0;
            nUpLoadSize = 0;
            nServiceID = 0;
            nFileCount = 0;
            nState = 0;
            nSpeed = 0;
            nCostTime = 0;
            szName = null;
        }
    };

Answer 4

如果你想保证它们二进制兼容，请使用StructLayout特性，http://msdn.microsoft.com/en-us/library/system.runtime.interopservices.structlayoutattribute.aspx。

Answer 5

我现在改成了：       public struct PROG_INFO
        {
            public int nProgID;
            public int nSize;
            public int nUpLoadSize;
            public int nServiceID;
            public int nFileCount;
            public int nState;
            public int nSpeed;
            public int nCostTime;
            public string szName;
            //public PROG_INFO(IntPtr wParam)
            PROG_INFO()
            {
                nProgID = 0;
                nSize = 0;
                nUpLoadSize = 0;
                nServiceID = 0;
                nFileCount = 0;
                nState = 0;
                nSpeed = 0;
                nCostTime = 0;
                szName = null;
            }
        }
但会出错的：错误 1 结构不能包含显式的无参数构造函数

Answer 6

[code]
public struct PROG_INFO
{
public int nProgID;
public int nSize;
……
PROG_INFO()
{
nProgID = 0;
nSize = 0;
nUpLoadSize = 0;
nServiceID = 0;
nFileCount = 0;
nState = 0;
nSpeed = 0;
nCostTime =0;
szName = NULL;
}
}
[/code]

Answer 7

  [StructLayout(LayoutKind.Sequential)]
public struct PROG_INFO
    {
        public int nProgID;
        public PROG_INFO(IntPtr wParam)
        {
            nProgID = 5;
        }
    }调用PROG_INFO info = new PROG_INFO((IntPtr)0);

Answer 8

其实看这个结构构造函数里的代码，转成C# struct，根本不必定义构造函数，直接下面这样定义就可以了，默认struct里的int字段为0，string字段为null的，不需要单独在定义构造函数给各字段赋值。
另外说明struct不能定义默认无参数的构造函数，只有class可以定义默认无参数的构造函数 public struct PROG_INFO
    {
        public int nProgID;
        public int nSize;
        public int nUpLoadSize;
        public int nServiceID;
        public int nFileCount;
        public int nState;
        public int nSpeed;
        public int nCostTime;        //对应c++的LPStr类型
        [System.Runtime.InteropServices.MarshalAs(System.Runtime.InteropServices.UnmanagedType.LPStr)]
        public string szName;      
    };

Answer 9

下面两种调用都可以，p1和p2的各个int型字段都是0，szName为null PROG_INFO p1 = new PROG_INFO();
 PROG_INFO p2;