我写了段生成0-3之间的随机数的代码但是我觉得不太好谁有更好的吗 谢谢了

Question

static void Main(string[] args)
        {
            Random randObj = new Random();
              int A;
            int B;
            int C;
            int D;
            //int now;
            for (int j = 0; j < 100; j++)
            {
                A = randObj.Next(0, 4);
                B = randObj.Next(0, 4);
                if (B != A)
                {
                    C = randObj.Next(0, 4);
                    if (C != A && C != B)
                    {
                        D = randObj.Next(0, 4);
                        if (D != A && D != B && D != C)
                        {
                            Console.WriteLine(A + "#" + B + "#" + C + "#" + D);
                            break;
                        }
                    }
                    else
                    {
                        continue;
                    }
                }
                else
                {
                    continue;
                }
            } 
        }

Answer 1

Random r = new Random();
int i = r.Next(3);

Answer 2

用while语句写 
你的可能出现极值，也就是100次没取道，就取不了了

Answer 3

            List<int> list = new List<int>();
            for (int index = 0; index < 4; index++)
            {
                list.Add(index);
            }            StringBuilder sb = new StringBuilder();
            Random random = new Random();            for (int index = 0; index < 4; index++)
            {
                int i = random.Next(0, list.Count);                if (sb.Length == 0)
                {
                    sb.Append(list[i]);
                }
                else
                {
                    sb.Append("#" + list[i]);
                }                list.Remove(list[i]);
            }            MessageBox.Show(sb.ToString());

Answer 4

好的方法是把 1,2,3,4放到一个数组中,随机打乱其顺序,然后再把数组中的值分配给ABCD,实现随机性.

Answer 5

用当前系统时间（时分秒）转换成int做种子

Answer 6

using System;
using System.Collections.Generic;
using System.Text;
using System.Collections;namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            int a, b, c;
            Hashtable ht = new Hashtable();            a = GetRandom();
            ht.Add(a, a);
            while (true)
            {
                b = GetRandom();
                if (!ht.ContainsValue(b))
                {
                    ht.Add(b, b);
                    break;
                }
            }
            while (true)
            {
                c = GetRandom();
                if (!ht.ContainsValue(c))
                {
                    ht.Add(c, c);
                    break;
                }
            }            Console.WriteLine(a);
            Console.WriteLine(b);
            Console.WriteLine(c);            Console.ReadLine();
        }        private static int GetRandom()
        {
            return new Random(DateTime.Now.Millisecond).Next(0, 4);
        }
    }
}

Answer 7

package number;import org.apache.struts.action.ActionMapping;
import org.apache.struts.action.ActionForm;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.Action;
import javax.servlet.http.*;
public class CreateNumberAction extends Action {
    public ActionForward execute(ActionMapping mapping, ActionForm form,
                                 HttpServletRequest request,
                                 HttpServletResponse response) {
        CreateNumberActionForm cform=(CreateNumberActionForm)form;
        HttpSession session=request.getSession();
        session.removeAttribute("message");
        int digits=Integer.parseInt(cform.getDigts());
        int secret_number=(int)(Math.random()*digits);
        session.setAttribute("secret_number",String.valueOf(secret_number));
       // throw new java.lang.UnsupportedOperationException(
               // "Method $execute() not yet implemented.");
        return mapping.findForward("guess");
    }
}
这是java里的 C#里和这差不多      int secret_number=(int)(Math.random()*digits);

Answer 8

比如1234四个数要随机抽取出来赋给ABCD,还要都不重复,按你的代码,到D是其实只能有1个数了,而你的程序还得重复N次才能取得这个数,显然浪费时间,而且当数多的时候更明显.
其实,这就是个洗牌的原理,4张牌分给4个人,把牌随机洗洗就发了ok.

Answer 9

public static T[] RandomSort<T>(T[] array)
    {
        int len = array.Length;
        System.Collections.Generic.List<int> list = new System.Collections.Generic.List<int>();
        T[] ret=new T[len];
        Random rand = new Random();
        int i = 0;
        while (list.Count < len)
        {
            int iter = rand.Next(0, len);
            if (!list.Contains(iter))
            {
                list.Add(iter);
                ret[i] = array[iter];
                i++;
            }
               
        }
        return ret;
    }

Answer 10

using System;
using System.Collections.Generic;
using System.Text;
using System.Collections;namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            List<int> list = new List<int>();            for (int i = 0; i < 4; i++)
            {
                list.Add(i);
            }            StringBuilder sb = new StringBuilder();
            while (true)
            {
                if (list.Count == 1)          // 到 D 了
                {
                    break;
                }                int index = new Random().Next(0, list.Count);
                sb.Append(list[index]);
                list.RemoveAt(index);                
            }            Console.WriteLine(sb.ToString());
            Console.ReadLine();
            
        }
    }
}

Answer 11

js:
arr=[0,..............................];
Array.prototype.Del=function(n) 
{
if(n<0)
    return this;
else
    return this.slice(0,n).concat(this.slice(n+1,this.length));
};for(var i=0;i<3;i++)
{
var index = Math.floor(Math.random()*(arr.length-1));
。//就很简单了arr=arr.Del(index);
}