在线求一方法.

Question

本帖最后由 sky1314 于 2013-01-23 17:21:16 编辑

Answer 1

int[] rooms = new int[4];
List<string> maps = new List<string>(new string[] { "室", "厅", "厨", "卫" });
string str = "2室2厅1卫";
MatchCollection mc = Regex.Matches(str, "(\\d+)(\\w)");
foreach (Match m in mc)
{
string key = m.Groups[2].Value;
int idx = maps.IndexOf(key);
if (idx > -1)
{
rooms[idx] = int.Parse(m.Groups[1].Value);
}
}
for (int i = 0; i < maps.Count; i++)
{
Console.WriteLine(rooms[i] + maps[i]);
}
貌似也没偷到什么懒~~~

Answer 2

   string str = "2室1厨1卫";
            var s = Regex.Matches(str, @"(?is)(?=.*?(?<room>\d+)室)?(?=.*?(?<hall>\d+)厅)?(?=.*?(?<kitchen>\d+)厨)?(?=.*?(?<toilet>\d+)卫)?.+").OfType<Match>().Select(t => new
            {
                room = t.Groups["room"].Value,
                hall = t.Groups["hall"].Value,
                kitchen = t.Groups["kitchen"].Value,
                toilet = t.Groups["toilet"].Value
            }).FirstOrDefault();

Answer 3

string str = "2室2厅1厨1卫";
                Match mc = Regex.Match(str, @"((?<room>\d*?)室|(?<hall>\d*?)厅|(?<kitchen>\d*?)厨|(?<toilet>\d*?)卫)*");
                var result = new {
                    room = mc.Groups["room"].Value,
                    hall = mc.Groups["hall"].Value,
                    kitchen = mc.Groups["kitchen"].Value,
                    toilet = mc.Groups["toilet"].Value
                };
                /*
                 + result { room = "2", hall = "2", kitchen = "1", toilet = "1" } <Anonymous Type>
                 */