请教个XmlTextReader滴问题

Question

有一个XML文件：
<Computer>
  <MAC>14:45:35:35:3</MAC>
  <IP>192.168.2.2</IP>
  <ComputerName>erterter</ComputerName>
</Computer>
<Computer>
  <MAC>34:35:45:45:43</MAC>
  <IP>10.18.2.</IP>
  <ComputerName>fdsgfgf</ComputerName>
</Computer>
<Computer>
  <MAC>00:1B:B9:56:87:38</MAC>
  <IP>34534553</IP>
  <ComputerName>3453455</ComputerName>
</Computer>
<Setting>
  <SubnetMask>255.255.255.0</SubnetMask>
  <DefaultGateway>345</DefaultGateway>
  <FirstDns>345</FirstDns>
  <SecondDns>345</SecondDns>
</Setting>
我想读取MAC的值为"00:1B:B9:56:87:38"的所有元素的值。
怎么办啊？

Answer 1

//读取XML数据 
            XmlNodeList nodeList = xmldoc.SelectNodes("Computer");
            StringBuilder strBody;
                  
            for (int row = 0; row < nodeList.Count; row++)
             {                
              
                MessageBox.Show(nodeList[row].Attributes["MAC"].Value.ToString());
                              
            }

Answer 2

FOR里
判断取出的值等于00:1B:B9:56:87:38

Answer 3

经断点调试发现，程序根本就没有进入for循环，因为根本无法读取出该节点：XmlDocument xmlDoc = new XmlDocument();
                XmlNodeList nodeList = xmlDoc.SelectNodes("Computer");
                MessageBox.Show(nodeList.Count.ToString());//0
                for (int i = 0; i < nodeList.Count; i++)
                {
                    string tempMac = nodeList[i].Attributes["MAC"].Value.ToString();
                    if (tempMac == mac)
                    {
                        MessageBox.Show(tempMac);
                        ip = nodeList[i].Attributes["IP"].Value.ToString();
                        computerName = nodeList[i].Attributes["ComputerName"].Value.ToString();
                        break;
                    }
                }
附XML文件：
<Computer>
  <MAC>14:45:35:35:3</MAC>
  <IP>192.168.2.2</IP>
  <ComputerName>erterter</ComputerName>
</Computer>
<Computer>
  <MAC>34:35:45:45:43</MAC>
  <IP>10.18.2.</IP>
  <ComputerName>fdsgfgf</ComputerName>
</Computer>
<Computer>
  <MAC>00:1B:B9:56:87:38</MAC>
  <IP>34534553</IP>
  <ComputerName>3453455</ComputerName>
</Computer>
<Setting>
  <SubnetMask>255.255.255.0</SubnetMask>
  <DefaultGateway>345</DefaultGateway>
  <FirstDns>345</FirstDns>
  <SecondDns>345</SecondDns>
</Setting>

Answer 4

   XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.Load(@"D:\Project\C#Test\WindowsApplication1\WindowsApplication4\XMLFile1.xml");
            XmlNodeList nodeList = xmlDoc.SelectNodes("/Computers/Computer");            for (int i = 0; i < nodeList.Count; i++)
            {
                    string tempMac = nodeList[i].ChildNodes[0].InnerText;
                    if(tempMac ==mac)
                    {
                         ip= nodeList[i].ChildNodes[1].InnerText;
computerName = nodeList[i].ChildNodes[2].InnerText;
                      break;
                    }
                
            }<?xml version="1.0" encoding="utf-8" ?>
<Computers>
  <Computer>
    <MAC>14:45:35:35:3 </MAC>
    <IP>192.168.2.2 </IP>
    <ComputerName>erterter </ComputerName>
  </Computer>
  <Computer>
    <MAC>34:35:45:45:43 </MAC>
    <IP>10.18.2. </IP>
    <ComputerName>fdsgfgf </ComputerName>
  </Computer>
  <Computer>
    <MAC>00:1B:B9:56:87:38 </MAC>
    <IP>34534553 </IP>
    <ComputerName>3453455 </ComputerName>
  </Computer>
  <Setting>
    <SubnetMask>255.255.255.0 </SubnetMask>
    <DefaultGateway>345 </DefaultGateway>
    <FirstDns>345 </FirstDns>
    <SecondDns>345 </SecondDns>
  </Setting>
</Computers>你的xml文件有问题啊你又2个Computer
但没有Computer的父节点..
帮你该了下

Answer 5

好的，已经改了。
但主要问题还没解决啊。
我现在想获取Computer节点数，用来循环，定位<MAC>00:1B:B9:56:87:38 </MAC> 
然后再取
<Computer> 
  <MAC>00:1B:B9:56:87:38 </MAC> 
  <IP>34534553 </IP> 
  <ComputerName>3453455 </ComputerName> 
</Computer>
的值