如何创建XML文档。

Question

XML文件的格式如下,请问如何在WINForm程序中创建?
<?xml version="1.0" encoding="gb2312"?>
<FilesInformation>
  <version>1.0.1818.42821 </version>
  <description>说明 </description>
  <FileItem
    FileName="name"
    FileVersion="sdf"
    FileLength="sdf"
    FileCreationTime="sd"
    />
</FilesInformation>在线等,即可结帖提问了三次，有两个50分的进不去，就剩30分了

Answer 1

http://www.cnblogs.com/yagebuqq/articles/1206496.html

Answer 2

            XmlDocument doc = new XmlDocument();
            doc.LoadXml("<?xml version=\"1.0\" encoding=\"gb2312\"?><FilesInformation></FilesInformation>");
            XmlElement newElem = doc.CreateElement("version");
            newElem.InnerText = "1.0.1818.42821 ";
            doc.DocumentElement.AppendChild(newElem);            newElem = doc.CreateElement("description");
            newElem.InnerText = "说明";
            doc.DocumentElement.AppendChild(newElem);            newElem = doc.CreateElement("FileItem");
            newElem.SetAttribute("FileName", "Name");
            newElem.SetAttribute("FileVersion", "sdf");
            doc.DocumentElement.AppendChild(newElem);            doc.Save("c:\\data.xml");

Answer 3

XmlDocument xml = new XmlDocument();
xml.Load("<?xml version=\"1.0\" encoding=\"gb2312\"?>....");

Answer 4

sting strXML = @"<?xml version="1.0" encoding="gb2312"?> 
<FilesInformation> 
  <version>1.0.1818.42821 </version> 
  <description>说明 </description> 
  <FileItem 
    FileName="name" 
    FileVersion="sdf" 
    FileLength="sdf" 
    FileCreationTime="sd" 
    /> 
</FilesInformation> 
"
然后利用文件流把这个XML写到文件里面！就这么创建啊 ？

Answer 5

        /// <summary>
        /// 写XML
        /// </summary>
        /// <param name="thisDataset"></param>
        /// <param name="path"></param>
        private void WriteXmlToFile(DataSet thisDataset, string path)
        {
            if (thisDataset != null)
            {
                try
                {
                    string filename = path + @"/B_PrintDef.xml";
                    System.IO.FileStream myFileStream = new System.IO.FileStream(filename, System.IO.FileMode.Create);
                    System.Xml.XmlTextWriter myWriter = new System.Xml.XmlTextWriter(myFileStream, Encoding.Unicode);
                    thisDataset.WriteXml(myWriter);
                    myWriter.Close();
                    mCtrl.mMessage.Message.MessageAlt("华远软件", "导出成功!");
                }
                catch (Exception ex)
                { 
                    mCtrl.mMessage.Message.MessageErr("华远软件", "异常提示", ex.Message);
                }
            }
        }

Answer 6

XmlTextWriter writer = new XmlTextWriter("F:\\XML.xml", System.Text.Encoding.UTF8);
            writer.WriteStartDocument();
            writer.WriteStartElement("Person");
            writer.WriteStartAttribute("ID", null);
            writer.WriteString("004");
            writer.WriteEndAttribute();
            writer.WriteStartElement("Name");
            writer.WriteStartAttribute("sex", null);
            writer.WriteString("fime");
            writer.WriteEndAttribute();
            writer.WriteString("testWriterName");
            writer.WriteEndElement();
            writer.WriteStartElement("Number");
            writer.WriteString("88888");
            writer.WriteEndElement();
            writer.WriteStartElement("City");
            writer.WriteString("testWriterCity");
            writer.WriteEndElement();
            writer.Flush();
            writer.Close();