xml read 的求助，先拜托，拜托，再拜托。

Question

<?xml version="1.0" encoding="utf-8"?>
<chart_data caption="CHFJPY - 1 Hour">
  <bar date="2008/05/28" time="11:00:00" open="100.81" high="100.89" low="100.70" close="100.81"/>
  <bar date="2008/05/28" time="12:00:00" open="100.81" high="100.84" low="100.73" close="100.77"/>
  <bar date="2008/05/28" time="13:00:00" open="100.77" high="100.86" low="100.70" close="100.78"/>
  <bar date="2008/05/28" time="14:00:00" open="100.78" high="100.83" low="100.73" close="100.81"/>
  <bar date="2008/05/28" time="15:00:00" open="100.81" high="100.92" low="100.76" close="100.92"/>
  <bar date="2008/05/28" time="16:00:00" open="100.92" high="100.92" low="100.80" close="100.82"/>
  <bar date="2008/05/28" time="17:00:00" open="100.82" high="100.91" low="100.80" close="100.87"/>
  <bar date="2008/05/28" time="18:00:00" open="100.87" high="100.94" low="100.81" close="100.90"/>
  <bar date="2008/05/28" time="19:00:00" open="100.90" high="100.95" low="100.85" close="100.86"/>
  <bar date="2008/05/28" time="20:00:00" open="100.86" high="100.97" low="100.85" close="100.97"/>
  <bar date="2008/05/28" time="21:00:00" open="100.97" high="101.02" low="100.89" close="101.00"/>
  <bar date="2008/05/28" time="22:00:00" open="101.00" high="101.01" low="100.94" close="101.00"/>
</chart_data>xml文件如上，我用了很多办法都无法读出来 `date="2008/05/28" time="11:00:00" open="100.81" high="100.89" low="100.70" close="100.81" 这几条数据。我的办法如下：
XmlTextReader reader = null;
            try
            {
              reader = new XmlTextReader(@"D:\222.xml");
               
                while (reader.Read())
                {
                    Console.WriteLine(reader.Name);
                    Console.WriteLine(reader.Value);
                                 }
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
            finally
            {
                reader.Close();
            }只能读取到：
xml
version="1.0" encoding="utf-8"chart_databarbarbarbarbarbarbarbarbarbarbarbarchart_data

Answer 1

   XmlTextReader reader = null;
List<string> list=new List<string>();
            try
            {
                reader = new XmlTextReader(@"D:\222.xml");                while (reader.Read())
                {                    if (reader.NodeType == XmlNodeType.Element)
                    {
                        if (reader.Name == "bar")
                        {
                            list.Add(reader.GetAttribute(0)+reader.GetAttribute(1)+reader.GetAttribute("open"));
                        }
                    }
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
            finally
            {
                reader.Close();
            } 

Answer 2

 XmlTextReader reader = null; 
List <string> list=new List <string>(); 
            try 
            { 
                reader = new XmlTextReader(@"D:\222.xml");                 while (reader.Read()) 
                {                     if (reader.NodeType == XmlNodeType.Element) 
                    { 
                        if (reader.Name == "bar") 
                        { 
                            list.Add("data=:"+reader.GetAttribute(0)+"time=:"+reader.GetAttribute(1)+"open=:"+reader.GetAttribute("open")); //下面我就不写了。
                        } 
                    } 
                } 
            } 
            catch (Exception ex) 
            { 
                MessageBox.Show(ex.Message); 
            } 
            finally 
            { 
                reader.Close(); 
            }