急,递归生成xml?

Question

    我想做一个目录树，然后保存的时候使用xml来保存嵌套结构，因为文件夹可以嵌套，所以不知道怎么设计类?
现在的想法是一个基类XNode 2个子类XFile和XFolder,XFile是文件,XFolder是文件夹
然后XFolder包含1个List<XNode>,不知道这样设计合理吗?而且这样设计感觉生成xml的算法好难.
有高手指教更好的办法吗?

Answer 1

迪规？什么  目录？
    XmlWriter writer = XmlWriter.Create(@"d:\a.xml");            writer.WriteStartDocument();
            
            writer.WriteStartElement("DriInfoList");
            InsertValue(writer, @"D:\other\HtmlParser");            writer.WriteEndElement();
            writer.WriteEndDocument();
            writer.Close(); private static void InsertValue(XmlWriter writer, string path)
        {
            DirectoryInfo dir = new DirectoryInfo(path);            DirectoryInfo[] dirinfo = dir.GetDirectories();            foreach (DirectoryInfo f in dirinfo)
            {
                writer.WriteStartElement("DriInfo");
                writer.WriteAttributeString("path", f.FullName);
                InsertFile(writer, f.GetFiles());
                InsertValue(writer, f.FullName);
                writer.WriteEndElement();
            }
        }        private static void InsertFile(XmlWriter writer, FileInfo[] file)
        {
            foreach (FileInfo f in file)
            {
                writer.WriteStartElement("FileInfo");
                writer.WriteAttributeString("FileName", f.FullName);
                writer.WriteString(f.Name);                writer.WriteEndElement();
            }
        }

Answer 2

呵呵，最后再加上标准的ＸＭＬ的标记开头
<? xml version="1.0" ....