一个字符串中去掉相同的字符

  String str="2,3,4,3,2,5";
            string[]  list = str.Split(',');
            string ret = string.Empty;            ArrayList list1 = new ArrayList();
            for (int i = 0; i < list.Length; i++)
            {
                if (!list1.Contains(list[i]))
                {
                    list1.Add(list[i]);
                }
            }            for (int i = 0; i < list1.Count; i++)
            {
                ret += list1[i] + ",";
            }
            Console.WriteLine(ret);
            Console.Read();

那是以下的字符串也可以用这样的方法？这个肯定是不行吧！
String str="2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2,"

string str = "2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2,";
            string[] stringArray  = str.Split(',');
            List<string> listString = new List<string>();
            foreach (string eachString in stringArray)
            {
                if (!listString.Contains(eachString))                    listString.Add(eachString);            }
            Console.WriteLine(string.Join(",", listString.ToArray()));
            Console.Read();

string str = "2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2,";
string[] stringArray = str.Split(',').Distinct().ToArray();
......

            //去除重复
            string txt = "2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2";
            //方法1
            var arr=txt.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries).GroupBy(x => x).Select(x => x.Key);
            foreach (var item in arr)
            {
                Console.WriteLine(item);
            }
            //方法2
            var arr2 = txt.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries).Distinct();
            Console.WriteLine("==========================");
            foreach (var item in arr2)
            {
                Console.WriteLine(item);
            }
            Console.Read();

string str = "2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2,";
string result=string.Empty;
Array.ForEach(str.Split(',').Distinct().ToArray(), s => result+=string.IsNullOrEmpty(s)?"":s + ",");
result = result.Trim().Substring(0, result.Length - 1);

我没加Linq，呵呵，没用过，抱歉

二重循环（冒泡排序）
for(int i=0;i<str.length()-1;i++)
{
   for(int j=0;j<str.length()-1-i;j++)
   {
      if(str[j]==str[j+1])
      {
        str[j+1]="";
      }
   }
}foreach(string s in str)
{
  if(s!="")
  {
    Console.Write(s+" ");
  }
}

是我没理解清楚还是什么情况？string a=",";for....
{
a=a+xxx+",";
if (xxxx)==-1
}不可以？

   String strinput="2，3，4，3，2，5";
            string query=String.Join("，",strinput.Split(new string[] { "，" }, StringSplitOptions.RemoveEmptyEntries).Distinct().OrderBy(x => x).ToArray());
            Console.WriteLine(query);

const string strinput = "2，3，4，3，2，5";
            var query = String.Join("，", strinput.Split(new[] { "，" }, StringSplitOptions.RemoveEmptyEntries).Distinct().OrderBy(x => x).ToArray());
            Console.WriteLine(query);
            Console.Read();

  class Program
    {
        static void Main(string[] args)
        {
            string str = "2,3,5,3,6,7,6,8,5,4,3,2,1,89,54,3,2,45,12,345345,123123,34,3,3,2,"; string[] stringArray = str.Split(',');
            string[] s = str.Split(',');
            string str1 = "";

            for (int i = 0; i < s.Length; i++)
            {
                for (int j = 0; j < i; j++)
                {

                    if (s[j] == s[i])
                    {                        s[j] = "";
                    }
                }
            }
            for (int i = 0; i < s.Length; i++)
            {
                str1=str1+s[i]+" ";
            }
                Console.WriteLine(str1);        }
    }
ok的，试试看

泛开里面的Contains方法

linq lamda表达式处理信息的整合具有很强的优势

string s = "234234234";
string tmp  ="";
foreach(char c in s)
  if(s.IndexOf(c)<0)
    tmp  += c;

用循环遍历字符串,运用indexOf()....这种东东太简单了,哎,,这种问题回的人这么多,足以说明论坛里菜鸟多,真正的大神太少了....

            string str = "2,3,5,3,6,7";             string[] s = str.Split(',');
            var  set  = new HashSet<string>(s);
            foreach(var k in  set)
                Console.Write("{0} ",k);

调试易

一个字符串中去掉相同的字符

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