.NET Remoting 出现异常!

Question

我用Activator.GetObject获得了一个服务器端对象
但是在调用其函数时出现RemotingException:Attempted to call a method declared on type 'ServerApplication.ServerInitor' on an object which exposes 'ServerApplication.UserMgr'.客户端代码:public void Logon()
{
ServerApplication.ServerInitor server =
(ServerApplication.ServerInitor)Activator.GetObject(typeof(ServerApplication.ServerInitor), "tcp://192.168.0.4:2739/chat");
         server.Log_on("a"); //该函数报异常
}
服务器端代码:
public class ServerInitor: MarshalByRefObject
{
  private UserMgr userManager;
   
   //中间代码略  public Guid Log_on(string nick)
  {
          return userManager.Logon(nick);
  }  public void Log_off(Guid guid)
  {
  userManager.Logoff(guid);
  }  public void Say(String guid, String content)
  {
  userManager.Say(guid, content);
  }

Answer 1

RemoteObject 没调用对把？
ServerApplication.ServerInitor server =
(ServerApplication.ServerInitor)Activator.GetObject(typeof(ServerApplication.ServerInitor), "tcp://192.168.0.4:2739/ServerInitor.Rem");

Answer 2

//仅供参考
/*  --------   server --------   */
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Collections;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Services;
using System.Runtime.Remoting.Channels.Tcp;
using Test04_Demo;try
{
   IDictionary ports = new Hashtable();
   ports["port"] = 8100;
   BinaryClientFormatterSinkProvider cs = new BinaryClientFormatterSinkProvider();
   BinaryServerFormatterSinkProvider ss = new BinaryServerFormatterSinkProvider();
   //TcpChannel channel = new TcpChannel(ports, cs, ss);
   channel = new TcpChannel(ports, cs, ss);
   ChannelServices.RegisterChannel(channel, false);
   Demo demo = new Demo();
   RemotingServices.Marshal(demo, "test04_demo.soap");
   lblOne.Text = "好极了,1号服务启动成功！";
}
catch
{
   lblOne.Text = "因网络或其他故障,未能成功启动服务";
}/* -------- client ----------*/
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using Test04_Demo;try
{
  demo = (Demo)Activator.GetObject(typeof(Demo), "tcp://localhost:8100/test04_demo.soap");
  if (demo != null)
  {
     lblInfo.Text = "恭喜,已经连接成功";
  }
}
catch
{
  lblInfo.Text = "抱歉,因故未能连接上";
}

Answer 3

RemotingServices.Marshal(demo, "test04_demo.soap");好! 就是这句话解决了大问题!
OK,散分