C#进度条问题

Question

现在我要生成A,B,C,D四个文件，每个文件所需要的时间各不相同，我如何用进度条控制生成的速度，在4个文件都生成好的时候，进度条刚刚100%，是不是要用什么进程去监视啊

Answer 1

MSDN查下"progressbar",LZ看看自己能不能解决~

Answer 2

你完成这个工作需要把生成文件的过程放到一个后台线程里面
当文件生成时，修改进度条的value值。全部生成完成设value值等于最大值即可。

Answer 3

private void Process()
{ String d = "afdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hra" +
"afdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hraafdfgtklghjoisglierhw 032u4-521u-2ut43p8ty3408y1284hra" +
"ejrt093u40tu30tu0348r-234uy593y394=248390w01-1\\543utp5w9tpfg873429y7otw348934bfsdla;'g4t347892729387`!IOT083848U03503Y8ore809340yt038yt0837uyt043809oasdhf89430t54g45y745te5t34y69098-090=-/uik7i8675674564565457567fr982^&$GBOR*hr3248t6h^&t096th3lthpse90929085u348t6-54tds0s9-093429-5693e0gu9-394-t3-93i4-t6j-k5jidstoproptefsdijf,/{+++"; byte[] b = System.Text.Encoding.UTF8.GetBytes(d + d + d + d + d);
int totalLength = b.Length; progressBar1.Maximum = totalLength*4; //运行4次,乘以四
progressBar1.Value = 0; //第一个文件
StreamWriter bw = new StreamWriter("D:\\aaa.txt");

for (int i = 0; i < totalLength; i++)
{
bw.BaseStream.WriteByte(b[i]);
progressBar1.PerformStep();
}
bw.Close();
//第二个文件
bw = new StreamWriter("D:\\bbb.txt"); for (int i = 0; i < totalLength; i++)
{
bw.BaseStream.WriteByte(b[i]);
progressBar1.PerformStep();
}
bw.Close();
//第三个文件
bw = new StreamWriter("D:\\ccc.txt"); for (int i = 0; i < totalLength; i++)
{
bw.BaseStream.WriteByte(b[i]);
progressBar1.PerformStep();
}
bw.Close();
//第四个文件
bw = new StreamWriter("D:\\ddd.txt"); for (int i = 0; i < totalLength; i++)
{
bw.BaseStream.WriteByte(b[i]);
progressBar1.PerformStep();
}
bw.Close();
}
}根本用不到多线程. 

Answer 4

        long totalFileSize = 0;
        int count = 0;
        private void button1_Click(object sender, EventArgs e)
        {
            List<string> list = new List<string>();
            list.Add("log.txt");
            list.Add("log2.txt");            foreach (string file in list)
            {
                if (!File.Exists(file)) continue;
                FileInfo info = new FileInfo(file);
                totalFileSize += info.Length;
            }            progressBar1.Maximum = (int)totalFileSize;
            progressBar1.Minimum = 0;            Thread thread = new Thread(new ParameterizedThreadStart(Foo));
            thread.IsBackground = true;
            thread.Start(list);
        }        private void Foo(object state)
        {
            List<string> list = state as List<string>;
            if (list != null)
            {
                foreach (string file in list)
                {
                    if (!File.Exists(file)) continue;
                    StreamReader reader = new StreamReader(file);
                    while (reader.Peek() > -1)
                    {
                        MethodInvoker mi = delegate
                        {
                            count += Encoding.Default.GetByteCount(reader.ReadToEnd());
                            progressBar1.Value = count;
                        };
                        Invoke(mi);
                    }
                }                if (progressBar1.Value == progressBar1.Maximum)
                {
                    MessageBox.Show("OK, it's done...");
                }
            }
        }

Answer 5

把四个文件的总长度取到，进度条的总长度就设成这个值。
生成文件时，用byte数组写 ，一次写多少就把进度条的value+上多少。