请教一个C#操作命令行的问题

Question

C#操作命令行，代码应该没有错误：
                  Process newProcess = new Process();
                newProcess.StartInfo.FileName = exeName;
                newProcess.StartInfo.UseShellExecute = false;
                newProcess.StartInfo.CreateNoWindow = true;
                newProcess.StartInfo.RedirectStandardOutput = true;
                newProcess.StartInfo.RedirectStandardInput = true;
                newProcess.StartInfo.RedirectStandardError = true;
                try
                {
                    newProcess.Start();
                    foreach (string item in argsLines)
                    {
                        newProcess.StandardInput.WriteLine(item);
                    }
                    newProcess.StandardInput.WriteLine("exit");
                    output = newProcess.StandardOutput.ReadToEnd();
                    newProcess.Close();
                }
                catch (Exception ex)
                {
                    MessageBox.Show(ex.Message);
                }但是现在有一个问题，就是我其中有些命令是启动另外一个软件下的，
如该系列命令为：cd d:\\,cd txtdo\m3\bin,tt930
tt930是txtdo软件中的一个操作命令，但是在C#中执行到tt930的时候程序就无法返回数据流了，但是在开始--》运行里面又是可以执行的
百思不得其解，希望有高手释疑，另外我想到的是可能原因是这个软件连接了公司的服务器，是不是在C#也要进行远程连接才能够链接到并且返回数据，欢迎讨论...

Answer 1

看看DOS下能不能用管道输出 然后获取文件看看

Answer 2

exeName是否等于cd   d:\\,cd   txtdo\m3\bin,tt930 。
如果是的话。不妨分开执行。

Answer 3

Process   newProcess   =   new   Process(); 
                                newProcess.StartInfo.FileName   =   "cmd.exe"; 
                                newProcess.StartInfo.UseShellExecute   =   false; 
                                newProcess.StartInfo.CreateNoWindow   =   true; 
                                newProcess.StartInfo.RedirectStandardOutput   =   true; 
                                newProcess.StartInfo.RedirectStandardInput   =   true; 
                                newProcess.StartInfo.RedirectStandardError   =   true; 
                                try 
                                { 
                                        newProcess.Start(); 
                                        newProcess.StandardInput.WriteLine("cd   d:\\,cd   txtdo\m3\bin,tt930");
                                        newProcess.StandardInput.WriteLine( "exit "); 
                                        output   =   newProcess.StandardOutput.ReadToEnd(); 
                                        newProcess.Close(); 
                                } 
                                catch   (Exception   ex) 
                                { 
                                        MessageBox.Show(ex.Message); 
                                } 
试试

Answer 4

                                    Process   newProcess   =   new   Process();
                                newProcess.StartInfo.FileName   =   exeName;
                                newProcess.StartInfo.UseShellExecute   =   false;
                                newProcess.StartInfo.CreateNoWindow   =   true;
                                newProcess.StartInfo.RedirectStandardOutput   =   true;
                                newProcess.StartInfo.RedirectStandardInput   =   true;
                                newProcess.StartInfo.RedirectStandardError   =   true;
                                try
                                {
                                        newProcess.Start();
                                        foreach   (string   item   in   argsLines)
                                        {
                                                newProcess.StandardInput.WriteLine(item);
                                        }
                                        newProcess.StandardInput.WriteLine( "exit ");
                                        output   =   newProcess.StandardOutput.ReadToEnd();
                                        newProcess.WaitForExit();
                                        newProcess.Close();
                                }
                                catch   (Exception   ex)
                                {
                                        MessageBox.Show(ex.Message);
                                } 试试看了。应该是还没有返回就结束了。

Answer 5

这样可以吗？                                                                Process   newProcess   =   new   Process(); 
                                newProcess.StartInfo.FileName   =   "cmd.exe"; 
                                newProcess.StartInfo.UseShellExecute   =   false; 
                                newProcess.StartInfo.CreateNoWindow   =   true; 
                                newProcess.StartInfo.RedirectStandardOutput   =   true; 
                                newProcess.StartInfo.RedirectStandardInput   =   true; 
                                newProcess.StartInfo.RedirectStandardError   =   true; 
                                try 
                                { 
                                        newProcess.Start(); 
                                        newProcess.StandardInput.WriteLine("cd   d:\\");
                                        newProcess.StandardInput.WriteLine("cd   txtdo\m3\bin");
                                        newProcess.StandardInput.WriteLine("tt930");
                                        newProcess.StandardInput.WriteLine( "exit"); 
                                        newProcess.StandardInput.Close();
                                        output   =   newProcess.StandardOutput.ReadToEnd(); 
                                        newProcess.Close(); 
                                } 
                                catch   (Exception   ex) 
                                { 
                                        MessageBox.Show(ex.Message); 
                                } 

Answer 6

Avoid  的根本就不能这样执行
lye2000000_super
昵称：我自横刀香甜笑 的也不行，我早就加过newProcess.WaitForExit()了，但是前面output都获取不了，所以不是这个原因
IThurricane 可以，非常感谢