<TR valign=top><TD><font face="Arial,Helvetica" size=2 def=2><b>
<A HREF="http://kevdb.infospace.com/_1_2E7HTNC047USVOY__intldb/wp/intl/detail/kevdb?KCFG=UK&OTMPL=/wp/results_detail.htm&FF=1&QFM=N&QN=john&QF=&QC=&QS=&actnav=org&showrec=1003322:resext&TQA=&TQC=chorley&TQS=&QP=&QST=&QHN=&wqp=&QZ=PR7+5RE&QK=1&QO=uk&QD=&DM=&KSN=intl-uk&KS=_0_n_0_0_Hrnd_1_3s_0_19qiua_149sPF&MinKS=_7BuK_0&MaxKS=_7DwR_0&CurKS=_7BuK_14i&QI=36&jnum=250+&jindex=35">Johnson Jeff</a>*
</b></font><br>
<font def="2" face="Arial,Helvetica" size=2>
<br>Chorley,  PR7 5-RE</font><br>
<A HREF="redirs_all.htm?pgtarg=pimabadd&QF=Jeff&QN=Johnson&QC=Chorley&QZ=PR7+5RE&QO=UK&QP=01257452237&actnav=org">
<font face="Arial,Helvetica" size=2> + Address Book</font></A>
</td><td align="right"><font def="3" face="Arial,Helvetica" size=3><b>01257452237</b>
</font><br><font face="Arial,Helvetica" size=2>
<a href="kmaint/kdbmod.html?D_KCFG=UK&D_KDB=intl-uk&D_RECNO=1003322%3Aresext&D_QP=01257452237&D_QN=Johnson&D_QF=Jeff&D_QC=Chorley&D_QZ=pr7+5re&D_QO=uk&&actnav=org">update/remove
</a></font></td></tr>用正则表达式,如怎么找出:
Johnson Jeff
Chorley,  PR7 5-RE
01257452237

解决方案 »

  1.   

    string s = @"<TR valign=top><TD><font face=""Arial,Helvetica"" size=2 def=2><b><A HREF=""http://kevdb.infospace.com/_1_2E7HTNC047USVOY__intldb/wp/intl/detail/kevdb?KCFG=UK&OTMPL=/wp/results_detail.htm&FF=1&QFM=N&QN=john&QF=&QC=&QS=&actnav=org&showrec=1003322:resext&TQA=&TQC=chorley&TQS=&QP=&QST=&QHN=&wqp=&QZ=PR7+5RE&QK=1&QO=uk&QD=&DM=&KSN=intl-uk&KS=_0_n_0_0_Hrnd_1_3s_0_19qiua_149sPF&MinKS=_7BuK_0&MaxKS=_7DwR_0&CurKS=_7BuK_14i&QI=36&jnum=250+&jindex=35"">Johnson Jeff</a>*</b></font><br><font def=""2"" face=""Arial,Helvetica"" size=2><br>Chorley,  PR7 5-RE</font><br><A HREF=""redirs_all.htm?pgtarg=pimabadd&QF=Jeff&QN=Johnson&QC=Chorley&QZ=PR7+5RE&QO=UK&QP=01257452237&actnav=org""><font face=""Arial,Helvetica"" size=2> + Address Book</font></A></td><td align=""right""><font def=""3"" face=""Arial,Helvetica"" size=3><b>01257452237</b></font><br><font face=""Arial,Helvetica"" size=2><a href=""kmaint/kdbmod.html?D_KCFG=UK&D_KDB=intl-uk&D_RECNO=1003322%3Aresext&D_QP=01257452237&D_QN=Johnson&D_QF=Jeff&D_QC=Chorley&D_QZ=pr7+5re&D_QO=uk&&actnav=org"">update/remove</a></font></td></tr>";
                Regex re = new Regex(@">(?<content>[^<\*].*?)<");
                foreach (Match m in re.Matches(s))
                    Console.WriteLine( m.Groups["content"].Value);
    可以得到Johnson Jeff
    Chorley,  PR7 5-RE
    01257452237
    除此之外,+ Address Book  update/remove也被取出来了。你想办法去掉吧
      

  2.   

    ruan_hg(阿阮) ,从这个地址来看,上面的方法好像不行哦:
    http://kevdb.infospace.com/_1_2TICU1D026IBWZ9__intldb/wp/results/kevdb?KCFG=UK&otmpl=/wp/results.htm&qsubcat=1&KSN=intl-uk&KS=_0_n_0_0_Hrnd_1_3s_0_19qiua_149sPF&MinKS=_7BuK_0&MaxKS=_7DwR_0&CurKS=_7BuK_14i&QN=john&QF=&QC=&QS=&QP=&QST=&QHN=&QTAPPEND=qn,qf&QFM=N&QK=5&QO=uk&QD=&DM=&qi=35