1,2,3,4,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,26

Question

1,2,3,4,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,26
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26以上有两组数，下面的行是正常的。请问各位怎样把第一行所缺的数字找出来？

Answer 1

ArrayList a1 = new ArrayList();//第一组
            ArrayList a2 = new ArrayList();//第二
            ArrayList a3 = new ArrayList();//缺少
            foreach (int i in a2)
            {
                if (a1.Contains(i))
                    continue;
                a3.Add(i);
            }

Answer 2

//参考代码:List<Int32> array01 = new List<int>(new int[]{ 1,2,3,4,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,26 });
List<Int32> array02 = new List<int>(new int[]{ 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26 });
List<Int32> result = new List<Int32>();for(int i=0;i<array02.Length;i++)
{
   if(!array01.Contains(array02[i]))
   {
      result.Add(array02[i]);
   }
}

Answer 3

谢谢shinaterry(簡簡單單..) 牛

Answer 4

shinaterry(簡簡單單..) 方法好一点，对于值类型的，使用ArrayList会装箱、拆箱的，这里用List好点。

Answer 5

洗洗睡了
有没有效率更高的方法啊 都是用两个for循环 没意思