我有一个xml文件,内容如下:
<?xml version="1.0" encoding="UTF-8"? >
<booklist >
<book >
<booktitle >Beethoven </booktitle >
<bookauthor >Maynard Solomon </bookauthor >
</book >
<book >
<booktitle >The Art of Shakespeare 's Sonnets </booktitle >
<bookauthor >Helen Vendler </bookauthor >
</book >
</booklist >
这个文件在本地,我现在要访问并遍历这个xml文件,显示在listview中,请问我怎么取到booktitle和bookauthor的值啊,如果有一些代码做参考,那就太好了。谢谢!
(我有一段例程,是对把子节点变成根结点的属性的这种xml访问遍历的(取name,取value),请问我这样的xml文件是否要转成子节点变成根结点属性的xml文档才能访问 还是直接有相关的函数可以使用)
谢谢了!
<?xml version="1.0" encoding="UTF-8"? >
<booklist >
<book >
<booktitle >Beethoven </booktitle >
<bookauthor >Maynard Solomon </bookauthor >
</book >
<book >
<booktitle >The Art of Shakespeare 's Sonnets </booktitle >
<bookauthor >Helen Vendler </bookauthor >
</book >
</booklist >
这个文件在本地,我现在要访问并遍历这个xml文件,显示在listview中,请问我怎么取到booktitle和bookauthor的值啊,如果有一些代码做参考,那就太好了。谢谢!
(我有一段例程,是对把子节点变成根结点的属性的这种xml访问遍历的(取name,取value),请问我这样的xml文件是否要转成子节点变成根结点属性的xml文档才能访问 还是直接有相关的函数可以使用)
谢谢了!
xd.Load("你的xml的文件路径");
XmlNode booksNode = xd.SelectSingleNode("booklist");
XmlNodeList books = booksNode.ChildNodes;
foreach (XmlNode book in books)
{
string booktitle = book.SelectSingleNode("booktitle").InnerText;
string bookauthor = book.SelectSingleNode("bookauthor").InnerText;
}
return; this.listView1.Items.Clear();
foreach (XmlNode node in root.ChildNodes)
{
if (node.Attributes["Name"].Value == this.textBox1.Text)
{
foreach (XmlNode item in node.ChildNodes)
{
this.listView1.BeginUpdate();
ListViewItem lvi = new ListViewItem(item.Attributes["Sequence"].Value);
lvi.SubItems.Add(item.Attributes["Name"].Value);
lvi.SubItems.Add(item.Attributes["ArriveTime"].Value);
lvi.SubItems.Add(item.Attributes["LeaveTime"].Value);
lvi.SubItems.Add(item.Attributes["TravelTime"].Value);
lvi.SubItems.Add(item.Attributes["TravelDistance"].Value);
this.listView1.Items.Add(lvi);
this.listView1.EndUpdate();
}
break;
}
}
xd.Load("你的xml的文件路径");
XmlNode booksNode = xd.SelectSingleNode("booklist");
XmlNodeList books = booksNode.ChildNodes;
foreach (XmlNode book in books)
{
string booktitle = book.SelectSingleNode("booktitle").InnerText;
string bookauthor = book.SelectSingleNode("bookauthor").InnerText;
}