两条小正则规则问题,解决即给分!

Question

1.取出邮件地址:string a="[email protected];[email protected];"
a由许多邮件地址组成,每个地址由;隔开,现想取出第个邮件地址,
这样写不正确:
Regex MyReg = new Regex(@"(\w)+\W(\w)+;{1}");2.查找某个字符在指定字符串中出现的次数string b="3     *        *        *     Request timed out.
4     *        *        *     Request timed out.
  5     *        *        *     Request timed out."现想查找*的个数及Request Timed out个数求解,解决给分

Answer 1

1题.试试 
Regex MyReg = new Regex(@"(\w)+\W(\w)+(\.(\w)+)+");

Answer 2

1
string a = "[email protected];[email protected];";
Text = Regex.Match(a, @"(\w+@\w+(\.\w+)+);").Result("$1"); //[email protected]
string b = ".......";
string key = "*";
Console.WriteLine((b.Length - b.Replace(key, "").Length) / key.Length);//9key = "Request timed out";
Console.WriteLine((b.Length - b.Replace(key, "").Length) / key.Length);//3

Answer 3

string a = "[email protected];[email protected];";            Regex rg = new Regex(@"(\w)+\W(\w)+\.(\w)+(?=;)");            MatchCollection mc = rg.Matches(a);
            foreach(Match m in mc)
            {
                Console.WriteLine(m.Value);            }

Answer 4

string b = "3     *        *        *     Request timed out.4     *        *        *     Request timed out.5     *        *        *     Request timed out.";            Regex rg2 = new Regex(@"\*");            MatchCollection mc2 = rg2.Matches(b);
            Console.WriteLine(mc2.Count);            Regex rg3 = new Regex(@" Request timed out");            MatchCollection mc3 = rg3.Matches(b);
            Console.WriteLine(mc3.Count);

Answer 5

这个电子邮件正则奇怪 - -·
难道这样的邮件格式就不标准么[email protected]

Answer 6

^([_a-z0-9.]*)@([a-z0-9-]+(\.[a-z0-9-]+)*\.[a-z]+(?=;))

Answer 7

@"(\w+(\.\w+)?@\w+(\.\w+)+);"
       ~~~~~~~~

Answer 8

\w+([-+.']\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*
这个是邮件的正则,用这个去匹配应该就可以了