求一个算法

Question

已知string a="1,2,3,4,...56"
要求得到一个string[] b 
其中b[0]="1,2,3,...10";
    b[1]="11,12,13,...20" ;
    ...
    b[4]="41,42,...50";
    b[5]="51,52,...56";
//总之将a里面以逗号分开的值10个10个的分开,最后组成一个sting[]private string[] getAnswer(string a)
{
   ...
   retrun b;
}
请教这个算法该怎么写,多谢!!!!!!!!!!!

Answer 1

string[] list=a.Split(",");
string[] b;
for(int i=0; i <list.Length; i++)
{
  if((list[i]%10!=0 || i==list.Length-1)
{
 b[i/10]+= list[i]+",";
}
else
{
b[i/10]+= list[i];
}}

Answer 2

string a="1,2,3,4,...56";
//
private string[] getAnswer(string a)
{
string[] c=a.split(new char[]{,});
int l=c.length;
int ll=l/10;
string[] b;
for (int i=0;i<ll;i++){
 for (int j=0;j<10;j++){
  b[i]+=c[i*10+j];
 }
}
return b;
}

Answer 3

private string[] getAnswer(string a)
        {
            string[] arr = a.Split( ',');
            int group = (arr.Length + 9) / 10;
            string[] result = new string[group];
            for (int i = 0; i < group; i++)
            {
                string s = "";
                for (int j = 0; j < 10; j++)
                {
                    int index = i * 10 + j;
                    if (index >= arr.Length)
                        break;
                    s += arr[index] + ",";
                }
                s = s.TrimEnd(',');
                result[i] = s;
            }
            return result;
        }

Answer 4

1,2,3,4,5,6,7,8,9,10
11,12,13,14,15,16,17,18,19,20
21,22,23,24,25,26,27,28,29,30
31,32,33,34,35,36,37,38,39,40
41,42,43,44,45,46,47,48,49,50
51,52,53,54,55,56
----
string a = string.Empty;
for (int i = 1; i <= 56; i++)
{
    a += "," + i.ToString();
}
a = a.Remove(0, 1); // 删除第一个","
int count = 0;
string t = string.Empty;
foreach (string s in a.Split(','))
{
    count++;
    if (count % 10 == 0)
    {
        t += "," + s;
        t = t.Remove(0, 1); // 删除第一个","
        Console.WriteLine(t);
        t = string.Empty;
    }
    else t += "," + s;
}
if (t != string.Empty)
{
    t = t.Remove(0, 1); // 删除第一个","
    Console.WriteLine(t);
}

Answer 5

string a="1,2,3,4,...56";
//
private string[] getAnswer(string a)
{
string[] c=a.split(new char[]{','});
int l=c.length;
int ll=l/10;
string[] b;
for (int i=0;i<ll;i++){
 for (int j=0;j<10;j++){
  b[i]+=c[i*10+j]+",";
 }
  b[i]=b[i].substring(0,b[i].length-1);
}
return b;
}

Answer 6

本来就是 固定值 何必搞循环 浪费b[0]={1,2,3,4,5,6,7,8,9,10}
b[1]={11,12,13,14,15,16,17,18,19,20}
b[2]={21,22,23,24,25,26,27,28,29,30}
b[3]={31,32,33,34,35,36,37,38,39,40}
b[4]={41,42,43,44,45,46,47,48,49,50}
b[5]={51,52,53,54,55,56}

Answer 7

发现我写的方法最失败...
using System;
using System.Collections.Generic;
using System.Text;
using System.Collections;namespace ConsoleApplication1
{
    public class Class1
    {
        private int numsize = 10;
        private int number = 0;
        public Class1() { }
        public Class1(int numsize)
        {
            this.numsize = numsize;
        }
        public int Numsize
        {
            get { return numsize; }
            set { numsize = value; }
        }
        public string[]  GetAnswer(string inputStr)
        { 
            string[] result = new string[GetNeedStringArrayNumber(GetNeedStringArrayELement(inputStr))]; //存放字符串数组
            int index = 0;  //当前字符串数组下标
            int cursor = 0; //数字统计
            for (int i = 0; i < inputStr.Length; i++)
            {
                if (!isComma(inputStr[i]))
                    SetNum(inputStr[i]);
                else
                {
                    ++cursor;
                    if (0 != cursor % numsize)
                    {
                        result[index] += number;
                        result[index] += ",";
                    }
                    else
                    {
                        result[index] += number;
                        ++index;
                    }
                    number = 0;
                }
            }
            result[index] += number;
            return result;
           
        }
        /// <summary>
        /// 获得真正字符串里存在的数字
        /// </summary>
        /// <param name="srcStr"></param>
        /// <returns></returns>
        private int GetNeedStringArrayELement(string srcStr)
        {
            int count = 0;
            for (int i = 0; i < srcStr.Length; i++)
            {
                if (isComma(srcStr[i]))
                    ++count;
            }
            return ++count;
        }
        /// <summary>
        /// 获得需要字符串数组的数量
        /// </summary>
        /// <param name="count"></param>
        /// <returns></returns>
        private int GetNeedStringArrayNumber(int count)
        {
            return count % numsize != 0 ? (count / numsize + 1) : (count / numsize);
        }
        /// <summary>
        /// 获得将字符串转换完毕后的数字
        /// </summary>
        /// <param name="c"></param>
        private void SetNum(int c)
        {
            number = number * 10 + ConvertToInt(c);
        }
        /// <summary>
        /// 转换字符为数字
        /// </summary>
        /// <param name="c"></param>
        /// <returns></returns>
        private int ConvertToInt(int c)
        {
            if (48 <= c && c <= 57)
                return c - 48;
            throw new Exception();
        }
        /// <summary>
        /// 判断是否是逗号
        /// </summary>
        /// <param name="c"></param>
        /// <returns></returns>
        private bool isComma(char c)
        {
            return c == ',' ? true : false;
        }
    }
}