根据字符串构建Tree结构

Question

china/beijing/haidian
china/beijing/chaoyang
china/shanghai
.....
上面是些类似这样的字符串结构,
现在我想构造类似 这样的结构china
     beijing
            haidian
            chaoyang
     shanghai
请问有什么好的建议 谢谢

Answer 1

DataSet ds=new DataSet();
ds.Table["City"].Columns.Add("CityId");
ds.Table["City"].Columns.Add("CityName");
ds.Table["CityRelation"].Columns.Add("ParentCityId");
ds.Table["CityRelation"].Columns.Add("ChildCityId");
ds.Table["CityRelation"].Columns.Add("Sequence");
然后把字符串填充进这个ds中
在用个函数就能遍历出这样的结构了
china
     beijing
            haidian
            chaoyang
     shanghai

Answer 2

楼上的是正解, 不过无给你一个更好的. 适合于像这样任何情况下的结构在Form1里 panel , treeView  , label1  的name =lbValue , label2  的name = lbTitle
 button1  , 
在Form2里有:textBox1, textBox2 的NAME 分别为:tbTitle,tbValue , button 为OK在Form1里. 
      private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
        {
            if (e.Node != null)
            {
                lbTitle.Text = e.Node.Text;
                if (e.Node.Tag != null)
                {
                    lbValue.Text = e.Node.Tag as string;                }
                else
                {
                    lbValue.Text = string.Empty;                }
            }
        }    private void button1_Click(object sender, EventArgs e)
        {
            using (Form2 form = new Form2())
            {
                if (form.ShowDialog() == DialogResult.OK)
                {
                    string title = form.Title;
                    string value = form.Value;                    if (tvTree.SelectedNode != null)
                    {
                        TreeNode node = tvTree.SelectedNode.Nodes.Add(title);                        node.Tag = value;
                    }
                }
            }
在Form2里:
      public string Title
        {
            get
            {
                return tbTitle.Text;
            }
        }        public string Value
        {
            get
            {
                return tbValue.Text;
            }
        }

Answer 3

请问下 读取字符串怎么构建这个字段的值呢?ds.Table["CityRelation"].Columns.Add("ParentCityId");

Answer 4

假设China为根节点 假设china节点ID为0
ds.Tables["City"].Rows.Add(1,"beijing")
ds.Tables["CityRelation"].Rows.Add(0,1,0)
ds.Tables["City"].Rows.Add(2,"shanghai")
ds.Tables["CityRelation"].Rows.Add(0,2,1)
ds.Tables["City"].Rows.Add(3,"guangdong")
ds.Tables["CityRelation"].Rows.Add(0,3,2)ds.Tables["City"].Rows.Add(4,"海淀")
ds.Tables["CityRelation"].Rows.Add(1,4,0)