C#打开图片问题.....

Question

if(dstOther.Tables[0].Rows[0][7]  !=  System.DBNull.Value  )  
                                                                       {  
                                                                                   this.ImageCount=(Byte[])dstOther.Tables[0].Rows[0][7];  
   
                                                                                   if(this.ImageCount!=null)  
                                                                                   {  
                                                                                               System.IO.MemoryStream  Ms  =  new  MemoryStream(this.ImageCount);  
   
                                                                                               Ms.Write(this.ImageCount,0,this.ImageCount.Length);  
 
                                                                                               this.img=(Image)Image.FromStream(Ms);  
                                                                                                 
                                                                                               this.picR4.Image=this.img  ;  
                                                                                   }  
                                                                       }  
 
 
上面代码运行到  
this.img=(Image)Image.FromStream(Ms);  
时出错提示说使用了无效参数.

Answer 1

你的这句
this.img=(Image)Image.FromStream(Ms);中Ms是图片的流吗？怎么觉得你没有得到Ms啊，只是声明了一个空的Ms数组.

Answer 2

this.ImageCount应该是一个整数，怎么能做为Write的参数呢？

Answer 3

注:MyTools.g_PhotoField为数据库表中的图象字段名称
//将图片保存到数据库中
if(this.picPhoto.Image==null)
{
m_DataRow[MyTools.g_PhotoField]=DBNull.Value;
}
else
{
try 
{
MemoryStream ms = new MemoryStream ();
picPhoto.Image.Save (ms, System.Drawing.Imaging.ImageFormat.Bmp);
byte [] myData = new Byte [ms.Length ];
ms.Position = 0;
ms.Read (myData,0,Convert.ToInt32 (ms.Length ));
m_DataRow[MyTools.g_PhotoField] = myData; }
catch(System.Exception ee) 
{
MessageBox.Show(ee.Message);
}
}//else//读取图象
if(this.m_DataRow[MyTools.g_PhotoField]!=DBNull.Value)
{
try
{
Byte[] byteBLOBData =  new Byte[0];
byteBLOBData = (Byte[])m_DataRow[MyTools.g_PhotoField];
MemoryStream stmBLOBData = new MemoryStream(byteBLOBData);
this.picPhoto.Image= Image.FromStream(stmBLOBData);
}
catch(Exception ex)
{
MessageBox.Show(ex.Message);
}
}
else
{
this.picPhoto.Image= null;
}