怎样在一个数组里面放7位数
string[,] s ={
{"5","8","6","17","22","30","25"},
{"5","9","4","14","18","1","5"},
{"15","1","16","7","12","30","25"},
{"5","8","25","17","15","25","4"},
{"15","8","25","17","18","25","4"},
{"5","25","17","17","32","25","4"}
};
找出数组里面每一列位数出现率最高的,和出现率最底的?
例如:第一列出现了3个5 和2个15
string[,] s ={
{"5","8","6","17","22","30","25"},
{"5","9","4","14","18","1","5"},
{"15","1","16","7","12","30","25"},
{"5","8","25","17","15","25","4"},
{"15","8","25","17","18","25","4"},
{"5","25","17","17","32","25","4"}
};
找出数组里面每一列位数出现率最高的,和出现率最底的?
例如:第一列出现了3个5 和2个15
解决方案 »
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{
public TextCount(string Text)
{
this.Text = Text;
Count = 0;
}
public string Text;
public int Count;
}
private static int CompareDinosByLength(TextCount A, TextCount B)
{
return B.Count - A.Count;
} private void button3_Click(object sender, EventArgs e)
{
string [,] s = {
{"5", "8", "6", "17", "22", "30", "25"},
{"5", "9", "4", "14", "18", "1", "5"},
{"15", "1", "16", "7", "12", "30", "25"},
{"5", "8", "25", "17", "15", "25", "4"},
{"15", "8", "25", "17", "18", "25", "4"},
{"5", "25", "17", "17", "32", "25", "4"}
};
for (int vCol = 0; vCol < 7; vCol++)
{
textBox1.Text += string.Format("第{0}列", vCol) + "\r\n";
List<TextCount> vTextCounts = new List<TextCount>();
for (int vRow = 0; vRow < 6; vRow++)
{
TextCount vTextCount = null;
for (int i = 0; i < vTextCounts.Count; i++)
{
if (vTextCounts[i].Text == s[vRow, vCol])
{
vTextCount = vTextCounts[i];
break;
}
}
if (vTextCount == null)
{
vTextCount = new TextCount(s[vRow, vCol]);
vTextCounts.Add(vTextCount);
}
vTextCount.Count++;
}
vTextCounts.Sort(CompareDinosByLength);
for (int i = 0; i < vTextCounts.Count; i++)
{
textBox1.Text += vTextCounts[i].Text + "=" +
vTextCounts[i].Count.ToString() + "\r\n";
}
}
}
,请给个代码例子
谢谢
没事多去跑跑TopCoder 现在真是怀念在学校无忧无虑的玩TopCoder的时光