最近在最邮件收取的一个东西,POP3从邮箱取邮件是能取到了,问题也出来了
以下为从163邮箱里取到的:
=====================================================================
+OK 1322 octets
Received:from quickmail.51job.com (unknown [61.129.48.175])
by mx6 (Coremail) with SMTP id wKjAOi4AzQeiRLtEH_Z9Bw==.18931S2;
Mon, 17 Jul 2006 16:04:50 +0800 (CST)
Received:(qmail 18474 invoked from network); 17 Jul 2006 08:04:48 -0000
Received:from unknown (HELO www14.51job.com) (192.168.1.26)
by quickmail.51job.com with SMTP; 17 Jul 2006 08:04:48 -0000
Received:(qmail 14106 invoked by uid 99); 17 Jul 2006 08:04:48 -0000
Date:17 Jul 2006 08:04:48 -0000
Message-ID:<[email protected]>
To:[email protected]
Subject:=?gb2312?B?KMjw0MfM4cq+LbTL08q8/r/JxNzKx8Csu/jTyrz+KQ==?==?gb2312?B?Rm9yZ2V0IFBhc3N3b3JkIQ==?=
MIME-Version:1.0
From:[email protected]
X-Mailer:Html Mime Mail Class
Content-Type:multipart/mixed;
charset="'gb2312'";
boundary="=_2b9c43c12b8831de20b62fd73f650a8b"
X-Brightmail-Tracker:AAAAAQAAAAQ=Sender: [email protected]
Sender:[email protected]=_2b9c43c12b8831de20b62fd73f650a8b
Content-Type: text/html;charset="gb2312"
Content-Transfer-Encoding: base64PHRhYmxlIGJvcmRlcj0xPjx0ciBzdHlsZT0iZm9udC1jb2xvcjpyZWQiPjx0ZD6x4LrFPC90ZD48
dGQ+u+HUscP7PC90ZD48dGQ+w9zC6zwvdGQ+PHRkPkVtYWlsPC90ZD48L3RyPjx0cj48dGQ+MS48
L3RkPjx0ZD55dWhhaWxhbjwvdGQ+PHRkPnl1aGFpbGFuPC90ZD48dGQ+bmFuNzc1NzBAMTYzLmNv
bTwvdGQ+PC90cj48L3RhYmxlPg==--=_2b9c43c12b8831de20b62fd73f650a8b--=====================================================================
问题如下:
1、如何能准确的定位到邮件的内容部分(就是直接把邮件正文剥离出来)?
2、如何从邮件的信息中找到哪些邮件是未读的,哪些是已读的?
3、POP3协议登陆的问题,163邮箱中,我用N年前的帐号密码直接登陆的时候是正常的,当用我刚申请的邮箱测试的时候,总是提示密码错误。难道要将密码加密后再通过POP3发送才行吗?望各位大虾不吝赐教!!!解决1、2问题者送分100!开贴另外送分!PS:特殊原因,不能用JMail这个组件。能提供DLL什么的也行..拜谢!
以下为从163邮箱里取到的:
=====================================================================
+OK 1322 octets
Received:from quickmail.51job.com (unknown [61.129.48.175])
by mx6 (Coremail) with SMTP id wKjAOi4AzQeiRLtEH_Z9Bw==.18931S2;
Mon, 17 Jul 2006 16:04:50 +0800 (CST)
Received:(qmail 18474 invoked from network); 17 Jul 2006 08:04:48 -0000
Received:from unknown (HELO www14.51job.com) (192.168.1.26)
by quickmail.51job.com with SMTP; 17 Jul 2006 08:04:48 -0000
Received:(qmail 14106 invoked by uid 99); 17 Jul 2006 08:04:48 -0000
Date:17 Jul 2006 08:04:48 -0000
Message-ID:<[email protected]>
To:[email protected]
Subject:=?gb2312?B?KMjw0MfM4cq+LbTL08q8/r/JxNzKx8Csu/jTyrz+KQ==?==?gb2312?B?Rm9yZ2V0IFBhc3N3b3JkIQ==?=
MIME-Version:1.0
From:[email protected]
X-Mailer:Html Mime Mail Class
Content-Type:multipart/mixed;
charset="'gb2312'";
boundary="=_2b9c43c12b8831de20b62fd73f650a8b"
X-Brightmail-Tracker:AAAAAQAAAAQ=Sender: [email protected]
Sender:[email protected]=_2b9c43c12b8831de20b62fd73f650a8b
Content-Type: text/html;charset="gb2312"
Content-Transfer-Encoding: base64PHRhYmxlIGJvcmRlcj0xPjx0ciBzdHlsZT0iZm9udC1jb2xvcjpyZWQiPjx0ZD6x4LrFPC90ZD48
dGQ+u+HUscP7PC90ZD48dGQ+w9zC6zwvdGQ+PHRkPkVtYWlsPC90ZD48L3RyPjx0cj48dGQ+MS48
L3RkPjx0ZD55dWhhaWxhbjwvdGQ+PHRkPnl1aGFpbGFuPC90ZD48dGQ+bmFuNzc1NzBAMTYzLmNv
bTwvdGQ+PC90cj48L3RhYmxlPg==--=_2b9c43c12b8831de20b62fd73f650a8b--=====================================================================
问题如下:
1、如何能准确的定位到邮件的内容部分(就是直接把邮件正文剥离出来)?
2、如何从邮件的信息中找到哪些邮件是未读的,哪些是已读的?
3、POP3协议登陆的问题,163邮箱中,我用N年前的帐号密码直接登陆的时候是正常的,当用我刚申请的邮箱测试的时候,总是提示密码错误。难道要将密码加密后再通过POP3发送才行吗?望各位大虾不吝赐教!!!解决1、2问题者送分100!开贴另外送分!PS:特殊原因,不能用JMail这个组件。能提供DLL什么的也行..拜谢!
1、POP3协议中,哪个命令可以直接得到当前连接的状态啊?就是怎么判断连接是否已经中断
2、怎么判断邮件是否已经收过。。就是如何判断是否是新邮件的问题。。哪位大哥指点一二啊!!就差这两问题了
命令 参数 状态 描述
------------------------------------------
USER username 认可 此命令与下面的pass命令若成功,将导致状态转换
PASS password 认可
APOP Name,Digest 认可 Digest是MD5消息摘要
------------------------------------------
STAT None 处理 请求服务器发回关于邮箱的统计资料,如邮件总数和总字节数
UIDL [Msg#] 处理 返回邮件的唯一标识符,POP3会话的每个标识符都将是唯一的
LIST [Msg#] 处理 返回邮件数量和每个邮件的大小
RETR [Msg#] 处理 返回由参数标识的邮件的全部文本
DELE [Msg#] 处理 服务器将由参数标识的邮件标记为删除,由quit命令执行
RSET None 处理 服务器将重置所有标记为删除的邮件,用于撤消DELE命令
TOP [Msg#] 处理 服务器将返回由参数标识的邮件前n行内容,n必须是正整数
NOOP None 处理 服务器返回一个肯定的响应
------------------------------------------
QUIT None 更新