在winFrom中的DataGrid如何达到在列中添加按钮???? 急..

Question

.net winform编程中,如何在datagrid列中添加一个button.就是像WebFrom中的模板列里添加功能按钮.谢谢. 
 我没做过winFrom的东西,今天一看winfrom的datagrid跟webForm的完全不是样.晕了. 
 急。。

Answer 1

直接添加列以后设置一下就OK了.这一列.celltype=button.

Answer 2

我这里我自己写的在datagrid添加ComboBox和DateTimerPick的代码：
//向DataGrid中添加ComboBox和DateTimerPicker
private void PopulateGrid(DataTable dt)
{
DataGridTableStyle DgStyle = new DataGridTableStyle();
DgStyle.MappingName = dt.TableName;
this.dataGrid1.TableStyles.Add(DgStyle);
DgStyle.RowHeadersVisible = true; DataGridTextBoxColumn dgtb = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[7];
ComboBox cmb = new ComboBox();
cmb.Cursor = Cursors.Arrow;
cmb.Dock = DockStyle.Fill;
            
DataGridTextBoxColumn dgtb0 = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[1];
            DateTimePicker dtime = new DateTimePicker();
dtime.Cursor = Cursors.Arrow;
dtime.Dock = DockStyle.Fill;
dgtb0.TextBox.Controls.Add(dtime);
dtime.ValueChanged +=new EventHandler(dtime_ValueChanged);
    
            Base bb = new Base(); string str1 = "select * from SectionInfo";
DataTable table1 = new DataTable();
table1 = bb.ExeSQLdt(str1); DataGridTextBoxColumn dgtb1 = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[2];
ComboBox cb1 = new ComboBox();
            cb1.DataSource = table1.DefaultView;
cb1.DisplayMember = "sName";
cb1.ValueMember = "sId";
cb1.Cursor = Cursors.Arrow;
cb1.DropDownStyle = ComboBoxStyle.DropDownList;
cb1.Dock = DockStyle.Fill;
dgtb1.TextBox.Controls.Add(cb1);
    cb1.SelectionChangeCommitted +=new EventHandler(cb1_SelectionChangeCommitted); DataGridTextBoxColumn dgtb2 = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[3];
ComboBox cb2 = new ComboBox();
cb2.DataSource = table1.DefaultView;
cb2.DisplayMember = "sName";
cb2.ValueMember = "sId";
cb2.Cursor = Cursors.Arrow;
cb2.DropDownStyle = ComboBoxStyle.DropDownList;
cb2.Dock = DockStyle.Fill;
dgtb2.TextBox.Controls.Add(cb2);
cb2.SelectionChangeCommitted +=new EventHandler(cb2_SelectionChangeCommitted); string str2 = "select * from JobInfo";
DataTable table2 = new DataTable();
table2 = bb.ExeSQLdt(str2); DataGridTextBoxColumn dgtb3 = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[4];
ComboBox cb3 = new ComboBox();
cb3.DataSource = table2.DefaultView;
cb3.DisplayMember = "JName";
cb3.ValueMember = "jsId";
cb3.Cursor = Cursors.Arrow;
cb3.DropDownStyle = ComboBoxStyle.DropDownList;
cb3.Dock = DockStyle.Fill;
dgtb3.TextBox.Controls.Add(cb3);
cb3.SelectionChangeCommitted +=new EventHandler(cb3_SelectionChangeCommitted); DataGridTextBoxColumn dgtb4 = (DataGridTextBoxColumn)this.dataGrid1.TableStyles[0].GridColumnStyles[5];
ComboBox cb4 = new ComboBox();
cb4.DataSource = table2.DefaultView;
cb4.DisplayMember = "JName";
cb4.ValueMember = "jId";
cb4.Cursor = Cursors.Arrow;
cb4.DropDownStyle = ComboBoxStyle.DropDownList;
cb4.Dock = DockStyle.Fill;
dgtb4.TextBox.Controls.Add(cb4);
cb4.SelectionChangeCommitted +=new EventHandler(cb4_SelectionChangeCommitted); } private void dtime_ValueChanged(object sender, EventArgs e)
{
    this.dataGrid1[this.dataGrid1.CurrentCell] = ((DateTimePicker)sender).Value.ToShortDateString();
} private void cb1_SelectionChangeCommitted(object sender, EventArgs e)
{
this.dataGrid1[this.dataGrid1.CurrentCell] = ((ComboBox)sender).SelectedItem.ToString();
}  
 
private void cb2_SelectionChangeCommitted(object sender, EventArgs e)
{
this.dataGrid1[this.dataGrid1.CurrentCell] = ((ComboBox)sender).SelectedItem.ToString();
}   private void cb3_SelectionChangeCommitted(object sender, EventArgs e)
{
this.dataGrid1[this.dataGrid1.CurrentCell] = ((ComboBox)sender).SelectedItem.ToString();
} 
 
private void cb4_SelectionChangeCommitted(object sender, EventArgs e)
{
this.dataGrid1[this.dataGrid1.CurrentCell] = ((ComboBox)sender).SelectedItem.ToString();
}