怎么样才能最快速的从下面xml文件中找出id<7的item结点

Question

<?xml version="1.0" encoding="utf-8" ?>
怎么样才能最快速的从下面xml文件中找出id<7的item结点select("id>7")
/item[id>7]全不灵，，TMD<items>
  <item><id>5</id>
    <name>0.15</name>
  </item>
  <item><id>6</id>
    <name>0.20</name>
  </item>
  <item><id>7</id>
    <name>0.30</name>
  </item>
  <item><id>8</id>
    <name>0.40</name>
  </item>
  <item><id>9</id>
    <name>0.50</name>
  </item>
<items>

Answer 1

帮楼主写了完整代码，注意你的提供的xml最后一个节点<items>要修改成</items>/*------------------------------------------------
http://blog.csdn.net/zhzuo        
--------------------------------------------------*/
namespace Zhzuo.VS2005Test.ConsoleTest
{
    class Program
    {
        private static DateTime ds;
        private static int i;
        private static bool n;        static void Main(string[] args)
        {
            string strXml = "<?xml version=\"1.0\"?>"
                + "<items>"
                    + "<item>"
                        +"<id>5</id>"
                        + "<name>0.15</name>"
                    + "</item>"
                    + "<item>"
                        +"<id>6</id>"
                        + "<name>0.20</name>"
                    + "</item>"
                    + "<item>"
                        +"<id>7</id>"
                        + "<name>0.30</name>"
                    + "</item>"
                    + "<item>"
                        +"<id>8</id>"
                        + "<name>0.40</name>"
                    + "</item>"
                    + "<item>"
                        +"<id>9</id>"
                        + "<name>0.50</name>"
                    + "</item>"
                + "</items>";
               
            XmlDocument doc = new XmlDocument();
            doc.LoadXml(strXml);
            XmlNodeList nodeList = doc.SelectNodes("//item[id>7]");
            
            Console.WriteLine(nodeList.Count);            Console.ReadLine();
        }     
    }   
        
}

Answer 2

用Xpath
或者弄到datatable里面用select方法