这段代码如何简化

Question

下面的代码的标签控件Label名称有规律，如何简化下面代码for (int i = 0; i < dataGridView1.Rows.Count; i++)
                {
                    switch (i)
                    {
                        case 0:
                            label1.Visible = true;
                            pictureBox1.Visible = true;
                            break;
                        case 1:
                            label2.Visible = true;
                            pictureBox2.Visible = true;
                            break;
                        case 2:
                            label3.Visible = true;
                            pictureBox3.Visible = true;
                            break;
                        case 3:
                            label4.Visible = true;
                            pictureBox4.Visible = true;
                            break;
                        case 4:
                            label5.Visible = true;
                            pictureBox5.Visible = true;
                            break;
                        case 5:
                            label6.Visible = true;
                            pictureBox6.Visible = true;
                            break;
                        case 6:
                            label7.Visible = true;
                            pictureBox7.Visible = true;
                            break;
                        case 7:
                            label8.Visible = true;
                            pictureBox8.Visible = true;
                            break;
                        case 8:
                            label9.Visible = true;
                            pictureBox9.Visible = true;
                            break;
                    }
                }

Answer 1

可以遍历datagrid中的控件,用FindControl(组合控件的名称)进行查找,然后赋属性

Answer 2

asp.net里有FindControl
我说的是c# WinForm
里边好像没有FindControl请高人指点一下

Answer 3

楼主,给你一些建议,也许对你有帮助:
    你可以建立一个label数组 一个pictureBox数组,
for (int i = 0; i < dataGridView1.Rows.Count; i++)
{
    label[i].Visible = true;
    pictureBox[i].Visible = true;}

Answer 4

for (i = 0; i < 8; i++)
 {
       Control[] ctl,ctl2;
       ctl = this.Controls.Find("label" + (i + 1).ToString(), true);//找到Lable
       ctl2 = this.Controls.Find("pictureBox" + (i + 1).ToString(), true);//找到PictureBox       ((Lable)ctl).Visible = true;
       ((PictureBox)ctl2).Visible = true;
 }

Answer 5

for (int i = 0; i < dataGridView1.Rows.Count; i++)
{
System.Web.UI.WebControls.Label lb = this.FindControl("Lable+"+i+"+");
System.Web.UI.WebControls.Image pictureBox = this.FindControl("pictureBox+"+i+"+");
lb.Visible = true;
pictureBox.Visible = true;

}

Answer 6

你可以将这些label和PictureBox放在一个panel上，然后通过
foreach (Control ctr in this.panel.Controls)
{
  //强制转换成label和picturebox
  //...
}
不过这样效率没有你上面的高，强制转换比较慢。