求助啊，socket编程，TCP网络传消息

如果用控制台输出服务器端的消息，程序就不继续运行了，不输出就可以继续运行，为什么啊？
private void AcceptMessage()
        {
            Console.WriteLine("开启新线程接收来自服务器的消息...");
            int len,i;
            NetworkStream netStream = new NetworkStream(ConnServer.getSocket());
            while (true)
            {
                try
                {
                    byte[] buffer = new byte[10000];
                    len = netStream.Read(buffer, 0, buffer.Length);
                    string[] message = Encoding.UTF8.GetString(buffer).Split( '|');                    for (i = 0; i < message.Length;i++ )
                    {
                        Console.WriteLine(message[i]);
                    }
                        switch (message[0])
                        {
                            case "ERR"://用户名或密码错误
                                LoginResult(message);
                                break;
                            case "EXT"://用户名重复登陆
                                LoginResult(message);
                                break;
                            case "LIST"://获取好友列表
                                GetFriendList(message);
                                break;
                            case "JOIN"://有新好友上线
                                JoinFriend(message);
                                break;
                            case "PRVC"://收到聊天信息
                                PrvChat(message);
                                break;
                            //以下部分尚未完成：
                            case "FREQ":
                                FileRequest(message);
                                break;
                            case "FACC":
                                AccFileSend(message);
                                break;
                            case "QUIT":
                                QuitFriend(message);
                                break;
                            case "GRPL":                                break;
                            case "GRPC":                                break;
                        }
                        netStream.Flush();
                }
                catch (Exception e)
                {
                    MessageBox.Show(e.Message);
                }
            }
        }