如题~谢谢

解决方案 »

  1.   

    System.Diagnostics.Process.Start("另外一个程序可执行文件路径");
      

  2.   

    using System.Diagnostics;public static void RunApplication(string fileName, string args, ProcessWindowStyle style)
            {
                ProcessStartInfo startInfo = new ProcessStartInfo(fileName);
                startInfo.WindowStyle = style;
                startInfo.Arguments = args;
                try
                {
                    Process.Start(startInfo);
                }
                catch
                {
                    return;
                }
            }
      

  3.   

    关闭:
    Diagnostics.Process.GetProcessesByName("myProName")[0].Kill()