初学请教:
建立一个按钮myButton,点击后弹出一个子窗口myWindow,怎样才能让按钮myButton再次被点击时弹出的还是刚才弹出的子窗口myWindow。我采用show(),好像不对。请问我该怎么写?private void myButton_Click(object sender, System.EventArgs e)
{
myWindow frmmyWindow=new myWindow();
frmmyWindow.MdiParent=this;
frmmyWindow.Show();
}
建立一个按钮myButton,点击后弹出一个子窗口myWindow,怎样才能让按钮myButton再次被点击时弹出的还是刚才弹出的子窗口myWindow。我采用show(),好像不对。请问我该怎么写?private void myButton_Click(object sender, System.EventArgs e)
{
myWindow frmmyWindow=new myWindow();
frmmyWindow.MdiParent=this;
frmmyWindow.Show();
}
{
//单件模式保证窗体只打开一次
if(instance == null)
{
instance = this;
}
else
{
this.Dispose();
instance.Activate();
return;
} InitializeComponent();
}
/// 单件模式的实现,静态初始化
/// </summary>
public class AddDepartment : System.Windows.Forms.Form
{
private static AddDepartment instance = null;
//返回需要的窗体类实例
public static AddDepartment GetInstance()
{
if(instance == null)
{
instance = new AddDepartment();
}
return instance;
} private void CloseWindow_Click(object sender, System.EventArgs e)
{
this.Close();
//关闭窗体时这句不能少
AddDepartment.instance = null;
}
}打开窗体的父窗体代码:
private void OpenWindow_Click(object sender, System.EventArgs e)
{
//取得窗体实例
AddDepartment frm = AddDepartment.GetInstance();
//显示窗体
frm.Show();
}