求助。。。对称字符串

Question

列出一个字符串中所有对称的字串，如输入：“a^_^aXyZZzy123321",期望：“a^_^a","^_^","ZZ","33","2332",  代码不会了。拜托高手代码和思路

Answer 1

        static void Main(string[] args)
        {
            string a = "a^_^aXyZZzy123321";            string[] subs = GetSubString(a);
            foreach (string subString in subs)
            {
                if (subString == new string(subString.ToCharArray().Reverse().ToArray()))
                    Console.WriteLine(subString);
            }
        }        public static string[] GetSubString(string s)
        {
            List<string> list = new List<string>();            for (int length = 2; length <= s.Length; length++)
            {
                for (int index = 0; index + length <= s.Length; index++)
                    list.Add(s.Substring(index, length));
            }            return list.ToArray();
        }
哈哈，闲来无聊，帮楼主写了个

Answer 2

我也来一个 static void Main(string[] args)
        {
            string str = "a^_^aXyZZzy123321";            for (int iStart = 0; iStart < str.Length - 1;  iStart++)
            {
                char head = str[iStart];//假设为头
                int iFind = str.IndexOf(head, iStart + 1);//找尾
                if (iFind > 0)
                {
                    string strSub = str.Substring(iStart, iFind - iStart + 1);
                    if (check(strSub))
                    {
                        Console.WriteLine(strSub);
                        continue;
                    }
                }
            }
            Console.Read();
             }        static bool check(string str)
        {
            for (int i = 0, j = str.Length - 1; i < j; i++, j--)
            {
                if (str[j] != str[i])
                {
                    return false;
                }
            }
            return true;
        }

Answer 3

 public ArrayList GetValues(string s)
        { 
            ArrayList al = new ArrayList();
            for (int i = 0; i < s.Length; i++)
            {
                for (int j = 2; j < s.Length - i; j++)
                {
                   //将对称值添加
                    if(GetResul(s.Substring(i, j)))
                    {
                        al.Add(s.Substring(i, j));
                    }
                    else
                    {                    }
                }
            }
            return al;
        }
        //判断是否对称
        public bool GetResul(string s)
        {
            bool res = false;
            if (s.Length % 2 == 0)
            {
                for (int i = 0; i < s.Length / 2; i++)
                {
                    if (s.Substring(i, 1) == s.Substring(s.Length-1 - i, 1))
                    {
                        res = true;
                    }
                    else
                    {
                        res = false;
                    }
                    if (res == false)
                    {
                        return false;
                    }
                }
                return res;
            }
            else
            {
                for (int i = 0; i < s.Length / 2+1; i++)
                {
                    if (s.Substring(i, 1) == s.Substring(s.Length-1 - i, 1))
                    {
                        res = true;
                    }
                    else
                    {
                        res = false;
                    }
                    if (res == false)
                    {
                        return false;
                    }
                }
                return res;
            }
        }