如何在textbox里显示txt文件的内容

Question

下面的代码只能显示文件的名字。如何显示内容呢？
private void 打开txt文件ToolStripMenuItem_Click(object sender, EventArgs e)
        {
            OpenFileDialog openFileDialog = new OpenFileDialog();
          OpenFileDialog.Filter = "文本文件(*.txt)|*.txt|所有文件(*.*)|*.*";            if (openFileDialog.ShowDialog() == DialogResult.OK)
            {                string fileName = openFileDialog.FileName;                textBox2.Text = fileName;
            }
        }

Answer 1

用System.IO.StringReader去读，看帮助

Answer 2

string path = @"D:\test.txt";//读取文件txt
            StringBuilder b = new StringBuilder();
            using (FileStream fs = new FileStream(path, FileMode.Open))
            {
                using (StreamReader sr = new StreamReader(fs))
                {
                    while (!sr.EndOfStream)
                    {
                        iLine++;
                        string sLine = sr.ReadLine();
                        if (sLine.Length < 1)
                        {
                            continue;
                        }
                        string sRecordKbn = sLine.ToString();//截取的数据
                     
                        b.Append(sRecordKbn); 
                    }
                }
            }
            textBox2.Text = b.ToString();

Answer 3

openFileDialog.FileName获取的是文件名，读出来的肯定是文件名啊，读内容不是这样滴

Answer 4

textBox2.Text=File.ReadAllText(fileName);

Answer 5

  textBox2.Text =  File.ReadAllText(openFileDialog.FileName,System.Text.Encoding.Default) ;

Answer 6

if (openFileDialog.ShowDialog() == DialogResult.OK)
  {
  string fileName = openFileDialog.FileName; 
Stream fs = new FileStream(filename, FileMode.Open);
            StreamReader sr = new StreamReader(fs,Encoding.GetEncoding("gb2312"));
           textBox2.Text = sr.ReadToEnd()
}