求Remoting怎么使用？最好给代码Thanks

Question

求Remoting怎么使用？最好给代码Thanks

Answer 1

所使用dll代码：
public class gxyremoting:System.MarshalByRefObject,gxyremotinginterface.remotinginterface
{
public gxyremoting()
{
Console.WriteLine("\n启动一个实例");
}
public DataSet GridData(string DataBaseName,string TableName)
{
Console.WriteLine("\n连接到数据库"+DataBaseName+"的表"+TableName);
string connetstring="workstation id=GAOXIAOYONG;packet size=4096;user id=sa;data source=GAOXIAOYONG;persist security info=False;initial catalog="+DataBaseName;
System.Data.SqlClient.SqlConnection conn=new SqlConnection(connetstring);
string strsql="select * from " +TableName;
DataSet ds=new DataSet();
System.Data.SqlClient.SqlDataAdapter adap=new SqlDataAdapter(strsql,conn);
adap.Fill(ds);
return ds;

}
}

Answer 2

客户端代码：
ChannelServices.RegisterChannel(new System.Runtime.Remoting.Channels.Tcp.TcpClientChannel());
ChannelServices.RegisterChannel(new System.Runtime.Remoting.Channels.Http.HttpClientChannel());
rf= (remotinginterface)Activator.GetObject(typeof(remotinginterface),"HTTP://192.168.0.123:9001/gxyremoting");
if( rf==null)
{
rf= (remotinginterface)Activator.GetObject(typeof(remotinginterface),"TCP://192.168.0.123:9000/gxyremoting");
}

Answer 3

服务器端代码：
TcpServerChannel tcpc=new  TcpServerChannel(9000);
System.Runtime.Remoting.Channels.Http.HttpServerChannel httpc=new System.Runtime.Remoting.Channels.Http.HttpServerChannel(9001);
RemotingConfiguration.RegisterWellKnownServiceType(typeof(gxyremoting),"gxyremoting",WellKnownObjectMode.SingleCall);
ChannelServices.RegisterChannel(tcpc);
ChannelServices.RegisterChannel(httpc);
Console.Write("启动服务器");
Console.ReadLine();