如何获取当前系统时间的周一和周五，请教高手啊。谢谢拉。

Question

如何获取当前系统时间的周一和周五

Answer 1

你是要判断是否周一周五吧？
DateTime.Now.DayOfWeek == DayOfWeek.Monday/Friday

Answer 2

for (int i=0; i<7; i++)
{
Console.WriteLine(DateTime.Today.AddDays((i-(int)DateTime.Today.DayOfWeek)).ToShortDateString());
}可以得到从周日到周六整整一周的日期
要是从周一到周五就
for (int i=1; i<6; i++)...

Answer 3

同意biliboy(我郁闷) 
DateTime.Now.DayOfWeek == DayOfWeek.Monday/Friday

Answer 4

public static void ConvertDateToWeek(DateTime date,out DateTime firstdate,out DateTime lastdate)
{
DateTime first=System.DateTime.Now;
DateTime last=System.DateTime.Now;
switch (date.DayOfWeek)
{
case System.DayOfWeek.Monday:
first=date.AddDays(-1);
last=date.AddDays(5);
break;
case System.DayOfWeek.Tuesday:
first=date.AddDays(-2);
last=date.AddDays(4);
break;
case System.DayOfWeek.Wednesday:
first=date.AddDays(-3);
last=date.AddDays(3);
break;
case System.DayOfWeek.Thursday:
first=date.AddDays(-4);
last=date.AddDays(2);
break;
case System.DayOfWeek.Friday:
first=date.AddDays(-5);
last=date.AddDays(1);
break;
case System.DayOfWeek.Saturday:
first=date.AddDays(-6);
last=date;
break;
case System.DayOfWeek.Sunday:
first=date;
last=date.AddDays(6);
break;
}
firstdate=first;
lastdate=last;
}

Answer 5

string str=string.Empty;
for(int i=0;i<7;i++)
{
switch (i)
{
case 0: str=System.DayOfWeek.Sunday.ToString();
weekday=CalendarBLLFacade.FormatDay(Convert.ToDateTime(firstdate));
break;
case 1:
str=System.DayOfWeek.Monday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(1));
break;
case 2:
str=System.DayOfWeek.Tuesday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(2));
break;
case 3:
str=System.DayOfWeek.Wednesday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(3));
break;
case 4:
str=System.DayOfWeek.Thursday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(4));
break;
case 5:
str=System.DayOfWeek.Friday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(5));
break;
case 6:
str=System.DayOfWeek.Saturday.ToString();
weekday=CalendarBLLFacade.FormatDay(firstdate.AddDays(6));
break;
}
DataRow dr=ds.Tables[0].NewRow();
ds.Tables[0].Rows.InsertAt(dr,i);
ds.Tables[0].Rows[i]["Week"]=str;
ds.Tables[0].Rows[i]["weekday"]=weekday;
}

Answer 6

System.DateTime dtNow = System.DateTime.Now;
System.TimeSpan tsMon = new TimeSpan( (int)(dtNow.DayOfWeek - System.DayOfWeek.Monday),0,0,0);
System.TimeSpan tsFri = new TimeSpan( (int)(System.DayOfWeek.Friday - dtNow.DayOfWeek),0,0,0); System.Console.WriteLine ( "Monday is " + (dtNow - tsMon).ToString() );
System.Console.WriteLine ( "Today is " + dtNow.ToString() );
System.Console.WriteLine ( "Today is " + (dtNow + tsFri).ToString() );

Answer 7

用存储过程实现:
CREATE procedure getFirstLastWeekDay
@currentDay datetime,--当前日期
@firstDay datetime output ,--当前日期所在周的第一个工作日(周一)
@lastDay datetime output --当前日期所在周的最后一个工作日(周五)
asset datefirst 1 --设置一周的第一天是周一select @firstDay=dateadd(dd,datediff(dd,'1900-01-01',@currentDay) - datepart(dw , @currentDay) + 1 , '1900-01-01')select @lastDay=dateadd(dd,datediff(dd,'1900-01-01',@currentDay)+(5-datepart(dw,@currentDay)),'1900-01-01')print @firstDay
print @lastday
GO

Answer 8

int t = (int)DateTime.Now.DayOfWeek;
DateTime moday = DateTime.Now.AddDays(1-t);
DateTime friday = DateTime.Now.AddDays(5-t);
DateTime now = DateTime.Now;