你的这种写法是vb中的用法: 10000 mod 89999 + 1如果必须要用mod的话,那么: System.Data.SqlTypes.SqlInt32 a = new System.Data.SqlTypes.SqlInt32(10000); System.Data.SqlTypes.SqlInt32 b = new System.Data.SqlTypes.SqlInt32(89999); System.Data.SqlTypes.SqlInt32 c = System.Data.SqlTypes.SqlInt32.Mod(a,b) + 1;结果是{10001}
int intTest = 10000 % 89999 + 1;
//intTest = 10001
10000 mod 89999 + 1如果必须要用mod的话,那么:
System.Data.SqlTypes.SqlInt32 a = new System.Data.SqlTypes.SqlInt32(10000);
System.Data.SqlTypes.SqlInt32 b = new System.Data.SqlTypes.SqlInt32(89999);
System.Data.SqlTypes.SqlInt32 c = System.Data.SqlTypes.SqlInt32.Mod(a,b) + 1;结果是{10001}