C#多线程同步 输出

Question

要睡觉去了，你lock了，肯定不可能实现了，任何一个线程逮住run都给你执行彻底了

Answer 1

用sleep和waitforsingleobject来实现还差不多

Answer 2

       List<Thread> t = new List<Thread>();//保存线程
        //输出变量0~30，必须是静态,否则每个线程一个是无法保证0~30顺序输出的
        static int outputIndex = 0;
       //同步对象,保证ouputIndex自增和输出的同步性
       static object syncLock = new object();        static void Main(string[] args)
        {
            Program p = new Program();
            p.Start();
            Console.ReadLine();
        }        public Program()
        {
            int threadCount = 6;
            for (int i = 0; i < threadCount; i++)
            {
                Thread therad = new Thread(Run);
                therad.Name = i.ToString();
                t.Add(therad);
            }
        }
        public void Start()
        {
            foreach (Thread tt in t)
            {
                tt.Start();
            }
        }
        public void Run()
        {
            try
            {
                    while (true)
                    {
                        lock (syncLock)
                            {
                                if (outputIndex < 30)
                                {   
                                    outputIndex++;
                                    Console.WriteLine("{0}:{1}", Thread.CurrentThread.Name, outputIndex);
                                    //不加Sleep单个线程就可以完成全部输出,
                                    //为了体现为多线程的效果需要适当的Sleep
                                    Thread.Sleep(1);
                                }
                                else
                                {
                                    break;
                                }
                             }
                    }
            }
            catch
            {
                
            }
            //后面的Stop毫无意义,已删除
        }

Answer 3

给你用双线程写个例子：(我觉得这样做实在是没有必要)using System;using System.Collections.Generic;using System.Text;using System.Threading; namespace ConsoleApplication1{    delegate int AddValueDele(object o);     class Program    {        public Program()        {            Value v=new Value();             AddValueDele a1 = new AddValueDele(AddValue);            AddValueDele a2 = new AddValueDele(AddValue);             while (v.number < 5)            {                IAsyncResult result = a1.BeginInvoke(v, null, null);                if (!result.IsCompleted)                {                    Console.WriteLine("a1 invoked.");                }                Console.WriteLine(a1.EndInvoke(result) );                 if (v.number < 5)                {                    IAsyncResult result2 = a2.BeginInvoke(v, null, null);                    if (!result2.IsCompleted)                    {                        Console.WriteLine("a2 invoked.");                    }                    Console.WriteLine(a2.EndInvoke(result2));                }            }        }         public int AddValue(object o)        {            Value v = (Value)o;            v.number++;            Thread.Sleep(2000);            //Console.WriteLine("number:{0}", v.number);            return v.number;        }         static void Main(string[] args)        {            Program p1 = new Program();            //Console.WriteLine( SetNumber(-2) );            Console.ReadLine();        }    }      public class Value    {        public int number=0;    }}
你可以运行一下，然后再考虑你的codes

Answer 4

呵呵  谢谢大家的支持啊  那个时候 急着弄所以很多地方发了贴 多数地方看了后  有点失望 居然把这个论坛  忘记了....
   不过现在才知道答案啊  4楼的 运行没问题  我第一次发的代码也是复制人家的 有点明白 又不是很明白  但是那个代码在WINFROM编程的时候  会出问题  4楼那个 我测试过没有问题...
  6楼发的 我也看了  不过还真是晕了  效果我也不知道是不是 因为看代码的时候 看了一般就没信心了 居然用了  IAsyncResult  也许是比较好  但是确实是太麻烦了  更何况没注释就没看了  对不起了 浪费你的劳动成果了