菜鸟问，为什么显示不出SQL SERVER 中的图片

我用C#在VS2003下开发WINFORM程序,想在SQL SERVER中插如照片并显示出来。#region 双击照片事件
private void pictureBox1_DoubleClick(object sender, System.EventArgs e)
{

OpenFileDialog openFileDialog1=new OpenFileDialog();
openFileDialog1.Filter="*.jpg;*.bmp;*.*|*.jpg;*.bmp;*.*";
if(openFileDialog1.ShowDialog()==DialogResult.OK)
{
try
{
Client client1=new Client();
client1.ClientUpdate(Item.clientId,openFileDialog1.FileName); Database dbphoto =new Database();
DataSet ds1=new DataSet();
ds1=dbphoto.GetDataSet("select photo from Client where clientId= "+Item.clientId.ToString(),"Client");
ShowImage(ds1,0,0); }
catch(Exception ex){MessageBox.Show(ex.Message);} }

} #endregion
...........................
以下为我调用的方法代码
............................
#region 更新用户, 修改客户的照片
/// <summary>
/// 更新用户, 修改客户的照片
/// </summary>
public void ClientUpdate(int clientId,string file)
{
System.IO.FileStream stream = new System.IO.FileStream(file, System.IO.FileMode.Open, System.IO.FileAccess.Read);
byte[] buffer = new byte[stream.Length];
stream.Read(buffer, 0, (int)stream.Length);
stream.Close(); Database db=new Database();
SqlParameter[] prams={
db.MakeInParam("@clientId",SqlDbType.Int,4,clientId),
db.MakeInParam("@photo",System.Data.SqlDbType.Image,16,buffer)

};

db.RunProc("Sp_Client_Update_Photo",prams); } #endregion //显示图像的方法
private void ShowImage(DataSet ds,int row,int column)
{ if(ds.Tables[0].Rows[row][column]!=Convert.DBNull)
{
byte[] bytes=(byte[])ds.Tables[0].Rows[row][column];
MemoryStream memStream=new MemoryStream(bytes);
Bitmap myImage=new Bitmap(memStream);
this.pictureBox1.Image=myImage;

}
else
{
this.pictureBox1.Image=null;
} }..................................................................我在调试过程中发现，在案双击照片事件中只要，执行到
Client client1=new Client();
client1.ClientUpdate(Item.clientId,openFileDialog1.FileName);Sql 数据库中我的photo (Image 16)字段中已有类似0xFFD8FFE000104A464946000102010048的内容，
可在执行ShowImage方法时，执行到
if(ds.Tables[0].Rows[row][column]!=Convert.DBNull)
{
byte[] bytes=(byte[])ds.Tables[0].Rows[row][column];
MemoryStream memStream=new MemoryStream(bytes);
还没有显示出问题,当执行到Bitmap myImage=new Bitmap(memStream);
时，系统自动提示：使用了无效的参数这是咋回事呀？？我都调试了好几天了。

解决方案 »

免费领取超大流量手机卡，每月29元包185G流量+100分钟通话, 中国电信官方发货

检查bytes是否有值;
以及memStream里的内容是否能构成一张图片信息;
如果你在一张图片流插入一个字节,那么也回出错;要更新图片建议对photo字段重新赋值
如河 “检查bytes是否有值及memStream里的内容是否能构成一张图片信息，一张图片流插入一个字节”我不知道咋写语句。我在Sql 数据库中找到了我的相应的photo (Image 16)字段,执行前为NULL,执行了Client client1=new Client();
client1.ClientUpdate(Item.clientId,openFileDialog1.FileName);其中已有类似0xFFD8FFE000104A464946000102010048的东西，是不是已将图片存入SQL了？
还是我取出的操作有问题？
下面的代码实现从SQL Server数据库提取图片并显示在DataGrid的功能。下面就是完整的代码，拷贝即可运行：<%@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<html>
<head>
<title>用户列表</title>
<script runat=server>
Sub Page_Load(sender As Object, e As EventArgs)
  If Not Page.IsPostBack Then
  BindGrid()
  End If
End SubPrivate Sub BindGrid()
  Dim strCnn As String = "Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;"
  Dim myConnection As SqlConnection = New SqlConnection(strCnn)
  Dim myCommand As SqlCommand = New SqlCommand("SELECT * FROM Person", myConnection)
  myCommand.CommandType = CommandType.Text
  Try
    myConnection.Open()
    DG_Persons.DataSource = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
    DG_Persons.DataBind()
    Catch SQLexc As SqlException
    Response.Write("Error occured while Generating Data. Error is " & SQLexc.ToString())
  End Try
End SubFunction FormatURL(strArgument) as String
  Return ("ReadImage.aspx?id=" & strArgument)
End Function
</script>
</head>
<body style="font: 9pt 宋体">
<h3 align=center>从数据库中取得照片并显示在DataGrid中</h3>
<form id="Form1" method="post" runat="server">
<asp:DataGrid ID="DG_Persons" AutoGenerateColumns=False Width="99%"
HeaderStyle-BackColor="#ff0000" HeaderStyle-Font-Bold="True" HeaderStyle-ForeColor="#ffffff"
ItemStyle-BackColor=Beige BorderColor="#000000" Runat=server HeaderStyle-HorizontalAlign=Center>
<Columns>
<asp:TemplateColumn HeaderText="姓名">
<ItemTemplate>
<asp:Label Runat="server"  Text='<%# DataBinder.Eval(Container.DataItem, "PersonName") %>' ID="Label1"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="电子邮件">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonEmail") %>' ID="Label2"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="性别">
<ItemTemplate>
<asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonSex") %>' ID="Label3"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="出生日期">
<ItemTemplate>
<asp:Label Runat="server"
  Text='<%# DataBinder.Eval(Container.DataItem, "PersonDOB") %>' ID="Label4"/>
</ItemTemplate>
</asp:TemplateColumn>
<asp:TemplateColumn HeaderText="照片">
<ItemTemplate>
<asp:Image Runat=server ID="Image1"  Width="150" Height="125"
ImageUrl='<%# FormatURL(DataBinder.Eval(Container.DataItem, "PersonID")) %>'  />
</ItemTemplate>
</asp:TemplateColumn>
</Columns>
</asp:DataGrid>
</form>
</body>
</html>ReadImage.aspx<%@ Page Language="vb" %>
<%@ Import Namespace="System.Data" %>
<%@ Import Namespace="System.Data.SqlClient" %>
<HTML>
<HEAD>
<script runat=server>
Public Sub Page_Load(sender As Object, e As EventArgs)
  Dim strImageID as String = Request.QueryString("id")
  Dim myConnection As New SqlConnection("Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;")
  Dim myCommand As New SqlCommand("Select PersonImageType, PersonImage from Person Where PersonID=" _
    + strImageID, myConnection)  Try
    myConnection.Open()
    Dim myDataReader as SqlDataReader
    myDataReader = myCommand.ExecuteReader(CommandBehavior.CloseConnection)
    Do While (myDataReader.Read())
    Response.ContentType = myDataReader.Item("PersonImageType")
    Response.BinaryWrite(myDataReader.Item("PersonImage"))
    Loop
    myConnection.Close()
    Catch SQLexc As SqlException
  End Try
End Sub
</script>
</HEAD>
<body>
<form runat="server" ID="Form1"></form>
</body>
</HTML>C# 版本DataGridShowImage.aspx<%@ Page language="c#" debug="true" Codebehind="DataGridShowImage.aspx.cs" AutoEventWireup="false"
Inherits="eMeng.Exam.DataGridShowImage.DataGridShowImage" %>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" >
<HTML>
<HEAD>
  <title>从数据库中取得照片并显示在DataGrid中</title>
  <meta name="GENERATOR" Content="Microsoft Visual Studio 7.0">
  <meta name="CODE_LANGUAGE" Content="C#">
  <meta name="vs_defaultClientScript" content="JavaScript">
  <meta name="vs_targetSchema" content="http://schemas.microsoft.com/intellisense/ie5">
</HEAD>
<body MS_POSITIONING="GridLayout">
<form id="DataGridShowImage" method="post" runat="server">
  <h3 align="center">从数据库中取得照片并显示在DataGrid中</h3>
  <asp:DataGrid ID="DG_Persons" AutoGenerateColumns="False" Width="99%" HeaderStyle-BackColor="#ff0000"
   HeaderStyle-Font-Bold="True" HeaderStyle-ForeColor="#ffffff" ItemStyle-BackColor="Beige"
    BorderColor="#000000" Runat="server" HeaderStyle-HorizontalAlign="Center">
  <Columns>
    <asp:TemplateColumn HeaderText="姓名">
      <ItemTemplate>
        <asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonName") %>' ID="Label1"/>
      </ItemTemplate>
    </asp:TemplateColumn>
    <asp:TemplateColumn HeaderText="电子邮件">
      <ItemTemplate>
        <asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonEmail") %>' ID="Label2"/>
      </ItemTemplate>
    </asp:TemplateColumn>
    <asp:TemplateColumn HeaderText="性别">
      <ItemTemplate>
        <asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonSex") %>' ID="Label3"/>
      </ItemTemplate>
    </asp:TemplateColumn>
    <asp:TemplateColumn HeaderText="出生日期">
      <ItemTemplate>
        <asp:Label Runat="server" Text='<%# DataBinder.Eval(Container.DataItem, "PersonDOB") %>' ID="Label4"/>
      </ItemTemplate>
    </asp:TemplateColumn>
    <asp:TemplateColumn HeaderText="照片">
      <ItemTemplate>
        <asp:Image Runat=server ID="Image1"
         ImageUrl='<%# FormatURL(DataBinder.Eval(Container.DataItem, "PersonID")) %>' />
      </ItemTemplate>
    </asp:TemplateColumn>
  </Columns>
  </asp:DataGrid>
</form>
</body>
</HTML>
(待续)
(接上)DataGridShowImage.aspx.csusing System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;
using System.Data.SqlClient;namespace eMeng.Exam.DataGridShowImage
{
/// <summary>
/// DataGridShowImage 的摘要说明。
/// </summary>
public class DataGridShowImage : System.Web.UI.Page
{
  protected System.Web.UI.WebControls.DataGrid DG_Persons;  private void Page_Load(object sender, System.EventArgs e)
  {
   // 在此处放置用户代码以初始化页面
   if(!this.IsPostBack)
   {
    BindGrid();
   }  }
  private void BindGrid()
  {
   string strCnn  = "Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;";
   SqlConnection myConnection = new SqlConnection(strCnn);
   SqlCommand myCommand = new SqlCommand("SELECT * FROM Person", myConnection);
   myCommand.CommandType = CommandType.Text;
   try
   {
    myConnection.Open();
    DG_Persons.DataSource = myCommand.ExecuteReader(CommandBehavior.CloseConnection);
    DG_Persons.DataBind();
   }
   catch(SqlException SQLexc)
   {
    Response.Write("提取数据时出现错误：" + SQLexc.ToString());
   }
  }
  protected string FormatURL(object strArgument)
  {
   return "ReadImage.aspx?id=" + strArgument.ToString();
  }#region Web Form Designer generated code
  override protected void OnInit(EventArgs e)
  {
   //
   // CODEGEN：该调用是 ASP.NET Web 窗体设计器所必需的。
   //
   InitializeComponent();
   base.OnInit(e);
  }
  /// <summary>
  /// 设计器支持所需的方法 - 不要使用代码编辑器修改
  /// 此方法的内容。
  /// </summary>
  private void InitializeComponent()
  {
   this.Load += new System.EventHandler(this.Page_Load);
  }
#endregion
}
}ReadImage.aspx<%@ Page language="c#" Codebehind="ReadImage.aspx.cs" AutoEventWireup="false"
Inherits="eMeng.Exam.DataGridShowImage.ReadImage" %>ReadImage.aspx.csusing System;
using System.Collections;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Web;
using System.Data.SqlClient;
using System.Web.SessionState;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.HtmlControls;namespace eMeng.Exam.DataGridShowImage
{
  /// <summary>
  /// ReadImage 的摘要说明。
  /// </summary>
  public class ReadImage : System.Web.UI.Page
  {
  private void Page_Load(object sender, System.EventArgs e)
  {
   // 在此处放置用户代码以初始化页面
   string strImageID = Request.QueryString["id"];
   SqlConnection myConnection = new SqlConnection("Data Source=.;Initial Catalog=mxh;User Id=sa;Password=;");
   SqlCommand myCommand = new SqlCommand("Select PersonImageType, PersonImage from Person Where PersonID="
    + strImageID, myConnection);   try
   {
    myConnection.Open();
    SqlDataReader myDataReader;
    myDataReader = myCommand.ExecuteReader(CommandBehavior.CloseConnection);
    if(myDataReader.Read())
    {
     Response.Clear();     Response.ContentType = myDataReader["PersonImageType"].ToString();
     Response.BinaryWrite((byte[])myDataReader["PersonImage"]);
    }
    myConnection.Close();
   }
   catch (SqlException SQLexc)
   {
   }
   Response.End();
  }
    #region Web Form Designer generated code
    override protected void OnInit(EventArgs e)
    {
      //
      // CODEGEN：该调用是 ASP.NET Web 窗体设计器所必需的。
      //
      InitializeComponent();
      base.OnInit(e);
    }

    /// <summary>
    /// 设计器支持所需的方法 - 不要使用代码编辑器修改
    /// 此方法的内容。
    /// </summary>
    private void InitializeComponent()
    {
      this.Load += new System.EventHandler(this.Page_Load);
    }
    #endregion
  }
}
byte[] bytes=(byte[])ds.Tables[0].Rows[row][column];
Image img= System.Drawing.Image.FromStream(new System.IO.MemoryStream(bytes));
看看Image是不是能够显示图片
使用DataList 或者 DataGrid 捆绑的不数据库的二进制流文件显示哎绑定的数据中
<asp:ImageButton ID="Picture" runat="server" Width="320" Height="240" CommandName="picture" CommandArgument='<%# DataBinder.Eval(Container.DataItem,"picture")%>' AlternateText='<%#DataBinder.Eval(Container.DataItem,"picture") %>' ImageUrl='<%#   FormatURL(DataBinder.Eval(Container.DataItem, "picturename").ToString())%>'>
</asp:ImageButton>