随机数

Question

Random ra = new Random(DateTime.Now.Millisecond);生成随机数
Random.Next (Int32, Int32)
for(int i=0;i<10;i++){}

Answer 1

Random ra = new Random(DateTime.Now.Millisecond);生成随机数
Random.Next (Int32, Int32)

Answer 2

int[] arr=new int[10];
            List<int> lst = new List<int>();
            while (true)
            {
                if (lst.Count == 10)
                {
                    break;
                }
                Random R1 = new Random(unchecked((int)System.DateTime.Now.Ticks));
                int i = R1.Next(1, 100);
                if (lst.Contains(i))
                {
                    continue;
                }
                lst.Add(i);
            }
            lst.CopyTo(arr, 0);

Answer 3

static void Main(string[] args)
        {
            ArrayList AList = new ArrayList();//定义可变长数组
            Random rd = new Random();
            int num;//将每次产生的随机数赋给此变量
            bool _bool = true;//判断是否有重复，初始时，数组中没有元素，不需要判断，固赋初值为True
            //产生8个不同的随机数
            while (AList.Count < 8)
            {
                num = rd.Next(0, 9);
                for (int i = 0; i < AList.Count; i++)
                {
                    //如果重复，跳出此循环，重新产生随机数
                    if (num == Convert.ToInt32(AList[i]))
                    {
                        _bool = false;
                        break;
                    }                    //如果与数组中该项不同，则为True
                    else
                    {
                        _bool = true;
                    }
                }
                //上面循环后，如果_bool仍为True，则说明此次产生的随机数在数组中无重复，则将此随机数赋给数组
                if (_bool == true)
                {
                    AList.Add(num.ToString());
                }
            }            //打印输出
            for (int i = 0; i < AList.Count; i++)
            {
                Console.WriteLine(AList[i]);
            }
            Console.ReadLine();
        }

Answer 4

C#生成指定数目的互不相同的随机数http://hi.baidu.com/feifeiyaqi3/blog/item/6e1d86170b72744321a4e926.html

Answer 5

int Count = 0;
            List<int> r = new List<int>();
            List<int> Result = new List<int>();
            int MaxCount = 30;
            while (true)
            {
                int i = new Random().Next(1, 100);
                if (!r.Contains(i))
                {
                    r.Add(i);
                    Count++;
                }
                if (Count >= MaxCount)
 break;
            }
            Result.AddRange(r.OrderBy(i => i));            Console.ReadKey();
        }

Answer 6

            System.Random R = new Random(unchecked((int)System.DateTime.Now.Ticks));
            List<int> L = new List<int>();
            int Count =0;
            int Temp = 0;            for (int i = 0; i < 10; i++)
            {
            Again:
                Temp = R.Next();
                if (L.Contains(Temp))
                {
                    goto Again;
                }
                else
                {
                    L.Add(Temp);
                    Count += 1;
                }
            }            int[] Ro = L.ToArray();
            foreach (int item in Ro)
            {
                Console.Write("{0}  ", item);
            }

Answer 7

不好意思 ，搞错了，我上面写的代码无需要 Count 变量。
应注释掉： //int Count =0;
         //Count += 1;