Ｃ＃开发的看门狗源码

Question

做个服务，能判断进程的busy状态

Answer 1

namespace WatchDog
{
    public partial class WatchDogService : ServiceBase
    {
        public static int count = 3;
        EventLog m_myLog = null;
        MSNService.httpmsnhelpdeskopencomcnSoapClient m_MsnService = null;
        QQService.httpqqhelpdeskopencomcnSoapClient m_QQservice = null;        System.Timers.Timer m_notifyTimer = null;
        //The unit is seconds.
        private int m_checkServiceIntervalTime = 180;        public int CheckServiceIntervalTime
        {
            get { return m_checkServiceIntervalTime; }
            set { m_checkServiceIntervalTime = value; }
        }        private bool m_ifChecking = false;        public WatchDogService()
        {
            InitializeComponent();
        }        protected override void OnStart(string[] args)
        {

Answer 2

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Answer 3

while(true)
{
Process[] oldP = Process.GetProcessesByName("msnmsger");
if (oldP.Length < 1) { MessageBox.Show("你的MSN停止運行!", "注意"); return; }
thread.sheep(1000);
}

Answer 4

  static Thread myThread;
        
        static void Main(string[] args)
        {
            myThread = new Thread(a);
            myThread.Start();
            Console.Read();
        }        static void a()
        {
            while (true)
            {
                Process[] oldP = Process.GetProcessesByName("msnmsger");
                if (oldP.Length < 1)
                {
                    Console.Write("你的MSN停止運行!"); 
                    //return;
                }
                Thread.Sleep(1000);
            }
        }