我有一段xml代码,怎样遍历显示在listview上?

Question

文件名:fileinfo.xmlxml代码:
<FileInfo Name="D:\WORKSHOP">
  <dir Name="HF_AWMAWorkshop20_huqiuwei" LastWriteTime="2005-2-5 17:42:34">
    <file Name="汉化说明.txt" LastWriteTime="2003-10-22 13:01:02" Length="4972" />
  </dir>
  <file Name="AKRIP32.DLL" LastWriteTime="2003-10-10 17:13:02" Length="71226" />
  <file Name="awmaw.chm" LastWriteTime="2003-8-17 0:36:30" Length="313409" /></FileInfo>
这是一个关于文件的属性读取,请问怎样分别遍历读出Name,LastWriteTime和Length在listview中显示啊??

Answer 1

2。读取xml
XmlDocument doc=new XmlDocument();
doc.Load("Filesheet.xml");
XmlNode node=doc.DocumentElement.FirstChild;
//XmlNamedNodeMap attrs=node.Attributes;
XmlAttributeCollection attrs=node.Attributes;
txtsite.Text=attrs[0].Value;
txtzhuji.Text=attrs[1].Value;
txtuser.Text=attrs[2].Value;
txtpassword.Text=attrs[3].Value;
txtzhushi.Text=attrs[4].Value;