foreach(int i in new int[]{1,2,3,4,5,6,7,8,9,0}) { if(i % 2 == 0) { Console.WriteLine(i.ToString()); } } Console.ReadLine();
可以考虑用集合的Contains 方法来代替in的这个用法
在 C C++ C# 都没有~
foreach(int i in 你的数组)if(数字==i){}
实际上思路是这样的: int yourNum = 5; foreach(int i in new int[]{1,2,3,4,5,6,7,8,9,0}) { if(i == yourNum) { Console.WriteLine(i.ToString()); } } Console.ReadLine();
int yourNum = 5; foreach(int i in new int[]{1,2,3,4,5,6,7,8,9,0}) { if(i == yourNum) { Console.WriteLine(i.ToString()); } } Console.ReadLine();
{
case 1:
case 2:
....}
{
if(i % 2 == 0)
{
Console.WriteLine(i.ToString());
}
}
Console.ReadLine();
int yourNum = 5;
foreach(int i in new int[]{1,2,3,4,5,6,7,8,9,0})
{
if(i == yourNum)
{
Console.WriteLine(i.ToString());
}
}
Console.ReadLine();
foreach(int i in new int[]{1,2,3,4,5,6,7,8,9,0})
{
if(i == yourNum)
{
Console.WriteLine(i.ToString());
}
}
Console.ReadLine();
{
if(数字==i){}
}
这个比较相似