MSXML2.XMLHTTP40Class xmlHttp = new XMLHTTP40Class();
string url = u.GetUrl();
if(url!="")
{
xmlHttp.open("POST", url+"?TNAME="+database+"."+tablename,false,"",""); xmlHttp.send("");
string res = xmlHttp.responseText;
u.Databading(res);
}
string url = u.GetUrl();
if(url!="")
{
xmlHttp.open("POST", url+"?TNAME="+database+"."+tablename,false,"",""); xmlHttp.send("");
string res = xmlHttp.responseText;
u.Databading(res);
}
解决方案 »
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